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nalin [4]
3 years ago
5

Iron(III) oxide reacts with carbon monoxide according to the equation: Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g) A reaction mixture initial

ly contains 22.00 g Fe2O3 and 14.10 g CO. Once the reaction has occurred as completely as possible, what mass (in g) of the excess reactant is left?
Chemistry
1 answer:
Bad White [126]3 years ago
4 0

Answer:

mass of excessive CO = 2.55 gram

Explanation:

Fe2O3(s)+3CO(g)→2Fe(s)+3CO2(g)

moles of Fe2O3 = mass / formula mass = 22.00/(56x2+16x3)=0.1375 (mol)

moles of CO = mass / formula mass = 14.1/(16+12) = 0.503

Fe2O3 reacts completely meanwhile CO is excessive.

mass of CO reacts = 3 x nFe2O3 x M = 3 x 0.1375 x (16+12) = 11.55 gram

mass of excessive CO = initial mass - reacted mass = 14.1 - 11.55 = 2.55 gram

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Answer:

Isopropylbenzene

Explanation:

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4 0
3 years ago
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Given the following thermodynamic data, calculate the lattice energy of LiCl:
tiny-mole [99]

Answer:

\boxed{\text{-862 kJ/mol}}

Explanation:

One way to calculate the lattice energy is to use Hess's Law.

The lattice energy U is the energy released when the gaseous ions combine to form a solid ionic crystal:

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We must generate this reaction rom the equations given.

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(3) Cl₂(g) ⟶ 2Cl(g)                     BE        =   243 kJ·mol⁻¹

(4) Li(g) ⟶Li⁺(g) +e⁻                   IE₁         =   520 kJ·mol⁻¹

(5) Cl(g) + e⁻ ⟶ Cl⁻(g)                EA₁       =  -349 kJ·mol⁻¹

Now, we put these equations together to get the lattice energy.

                                                <u>E/kJ </u> 

(5) Li⁺(g) +e⁻ ⟶ Li(g)                520

(6) Li(g) ⟶ Li(s)                         -161

(7) Li(s) + ½Cl₂(g) ⟶ LiCl(s)     -409

(8) Cl(g) ⟶ ½Cl₂(g)                   -121.5

(9) Cl⁻(g) ⟶ Cl(g) + e⁻               <u>+349</u>

      Li⁺(g) +  Cl⁻(g) ⟶ LiCl(s)     -862

The lattice energy of LiCl is \boxed{\textbf{-862 kJ/mol}}.

3 0
3 years ago
I. Choose the letter of the correct answer. Write your answer on a separate sheet of paper.
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6 0
2 years ago
What is the mass, in grams, of 28.58 mL of acetone?
Vedmedyk [2.9K]
<span>If you look up the density of Acetone (Propanone in IUPAC names) you will find it is 0.7925g/cm3. This is the same as 0.7925g/ml. 

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7 0
3 years ago
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Lena [83]

Answer:

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Explanation:

okay?.........................................

4 0
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