Answer:
Here is the answer ⬆️⬆️⬆️⬆️⬆️
Answer is none of the above
Answer:
moles of camphor = 0.0522 moles
Explanation:
<u>Data:</u>
MW camphor= 152 g/mol
V solution = 1.32 L
M solution = 6.01 M
moles solute = ?
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To calculate the moles of camphor, you must first know the grams of solute (camphor) that exist in the solution, this is calculated from the molarity equation:
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From there the grams of the solute (camphor) are cleared:
-
Then by means of the molecular weight (MW) equation the moles can be obtained:
Answer:
The answer to the question is
Chlorine Cl₂
Explanation:
Graham's Law of effusion states that the rate of effusion of a gas is inversely proportional to the square root of the molar mass
0.238 =
Therefore M₁ = 4÷0.238² = 70.61
Hence the mass of the gas is 70.61, that is X₂ = 70.61 or the molar mass of the element X = 70.61÷2 = 35.308 ≅35.453 Hence the gas is chlorine Cl₂
Answer:
104.84 moles
Explanation:
Given data:
Moles of Boron produced = ?
Mass of B₂O₃ = 3650 g
Solution:
Chemical equation:
6K + B₂O₃ → 3K₂O + 2B
Number of moles of B₂O₃:
Number of moles = mass/ molar mass
Number of moles = 3650 g/ 69.63 g/mol
Number of moles = 52.42 mol
Now we will compare the moles of B₂O₃ with B from balance chemical equation:
B₂O₃ : B
1 : 2
52.42 : 2×52.42 = 104.84
Thus from 3650 g of B₂O₃ 104.84 moles of boron will produced.