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monitta
3 years ago
15

Which expression represents the percent by mass of nitrogen in NH 4 NO 3 ?

Chemistry
1 answer:
katrin2010 [14]3 years ago
8 0

Answer: a) \frac{28gN}{80gNH_4NO_ 3}\times 100\%

Explanation: Mass percentage is defined as the ratio of the mass of the particular element to the total mass of the substance multiplied by 100.

{\text{mass percentage}=\frac{\text{mass of the element}}{\text{Total mass}}\times {100}

mass of nitrogen[2 atoms of N] = 28 g

Total mass of NH_4NO_ 3=2\times {\text {Mass of nitrogen}}+4\times {\text {mass of hydrogen}}+3\times {\text {mass of oxygen}}

=2\times 14+4\times 1 +3\times 16=80 g

{\text{mass percentage}=\frac{28}{80}\times {100}\%




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Answer A) : We have to calculate the number of moles of Benzene involved in the reaction,

30 g / 78 moles of benzene = 0.384 moles


For bromine it will be the same process,

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By observing the reaction given above we can say that the reaction ratio of bromine and benzene is 1 : 1


We need to find the mass of bromobenzene,

which should be, 6(12) + 5 (1)+ 79.90 = 156.9 g/mol


So, the mass of bromobenzene will be 156.9 g/mol X 0.3846 mol = 60.343 g


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Here, we can say that we got 93.96 % of actual yield.


As we know it is impossible to get 100% yield in any reaction.

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