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IgorLugansk [536]
2 years ago
8

What is 5% of 20? I need help

Mathematics
1 answer:
Inessa [10]2 years ago
8 0

Answer:10

Step-by-step explanation:

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What is the inverse of f(x)=(-2x+2)/(x+7)?
Nana76 [90]

By applying the concept of the inverse of a function and <em>algebraic</em> handling, we conclude that the inverse of f(x) = (- 2 · x + 2)/(x + 7) is g(x) = (- 7 · x + 2)/(x + 2).

<h3>How to find the inverse of a function</h3>

In this question we have a <em>rational</em> function f(x) and finding its inverse consists in clearing x in terms of f(x). Prior any algebraic handling, we need to apply the following substitutions:

x \to y

f(x) \to x

x = \frac{-2\cdot y + 2}{y+7}

x · (y + 7) = - 2 · y + 2

x · y + 7 · x = - 2 · y + 2

2 · y + x · y = - 7 · x + 2

y · (2 + x) = - 7 · x + 2

g(x) = \frac{- 7\cdot x + 2}{x + 2}

By applying the concept of the inverse of a function and <em>algebraic</em> handling, we conclude that the inverse of f(x) = (- 2 · x + 2)/(x + 7) is g(x) = (- 7 · x + 2)/(x + 2).

To learn more on inverses: brainly.com/question/7181576

#SPJ1

4 0
1 year ago
Really need this todayyyyyy
Bond [772]

Answer:

Q3: x1=2+i, x2=2-i Q4: x1=-3/2+i, x2=-3/2-i

Step-by-step explanation:

x^{2} - 4x + 5 =0

( 4± \sqrt{16 - 4*1*5} ) / 2 = (

x1= 2+i

x2= 2-i

2x^{2} +6x + 5 =0

( -6 ± \sqrt{36 - 4*2*5} ) / 4 = (-6 ± \sqrt{-4} )/4= (-3 ± i)/2

x1 = -3/2 +i

x2 = -3/2 -i

7 0
3 years ago
Read 2 more answers
Thanks in advance if you help me!
8090 [49]
D) Definition of Equilateral Triangle
e) Vertical Angles
f1) ΔTVS <span>≅ </span>ΔUVR
f2) Side Angle Side Postulate
g) Definition of Congruent Triangles

Hope that helps!
4 0
3 years ago
122 - 4(6) +1<br> 112p hellllllp
Rasek [7]

Answer:

99

Step-by-step explanation:

U will do the one outside first

122+1-4(6)

=123-24

= 99

7 0
2 years ago
Which 2 equations would you use to solve this system?
slega [8]

Answer:

x-y=4

and

x+y=32 is <u>your</u><u> </u><u>equation</u>

<u>d</u><u>i</u><u>f</u><u>f</u><u>e</u><u>r</u><u>e</u><u>n</u><u>c</u><u>e</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u> </u><u>=</u><u>x-y</u><u> </u><u>is</u><u> </u><u>equal</u><u> </u><u>to</u><u> </u><u>4</u>

<u>s</u><u>u</u><u>m</u><u> </u><u>o</u><u>f</u><u> </u><u>t</u><u>w</u><u>o</u><u> </u><u>n</u><u>u</u><u>m</u><u>b</u><u>e</u><u>r</u><u>=</u><u>x</u><u>+</u><u>y</u><u> </u><u>i</u><u>s</u><u> </u><u>e</u><u>q</u><u>u</u><u>a</u><u>l</u><u> </u><u>t</u><u>o</u><u> </u><u>3</u><u>2</u>

<u>x</u><u>-</u><u>y</u><u>=</u><u>4</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>1</u><u>)</u>

<u>x</u><u>+</u><u>y</u><u>=</u><u>3</u><u>2</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>.</u><u>(</u><u>2</u><u>)</u>

<u>a</u><u>d</u><u>d</u><u>i</u><u>n</u><u>g</u><u> </u><u>equation</u><u> </u><u>1</u><u> </u><u>a</u><u>n</u><u>d</u><u> </u><u>2</u>

<u>x</u><u>-</u><u>y</u><u> </u><u>+</u><u>x</u><u>+</u><u>y</u><u>=</u><u>4</u><u>+</u><u>3</u><u>2</u>

<u>2</u><u>x</u><u>=</u><u>3</u><u>6</u>

<u>x</u><u>=</u><u>3</u><u>6</u><u>/</u><u>2</u><u>=</u><u>1</u><u>6</u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

<u>s</u><u>u</u><u>b</u><u>s</u><u>t</u><u>i</u><u>t</u><u>u</u><u>t</u><u>i</u><u>n</u><u>g</u><u> </u><u>value</u><u> </u><u>of</u><u> </u><u>y</u><u> </u><u>in</u><u> </u><u>equation</u><u> </u><u>1</u>

<u>1</u><u>6</u><u>-</u><u>y</u><u>=</u><u>4</u>

<u>1</u><u>6</u><u>-</u><u>4</u><u>=</u><u>y</u>

<u>y</u><u>=</u><u>1</u><u>2</u><u> </u><u>a</u><u>n</u><u>s</u><u>w</u><u>e</u><u>r</u>

4 0
2 years ago
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