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3 years ago

Anna divided a sheet of paper into 5 equal sections and colored 3 sections blue . What percent is that and it =60

Mathematics

1 answer:

Dimas [21]3 years ago

8 0

Answer:

she colored in 60% of the paper blue and left 40% of the paper blank

Step-by-step explanation:

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The City of Oz has to repaint its cylinder-shaped water tower. Only the top and sides need to be painted. If the water tower has

scoundrel [369]

Thank you for posting your question here at brainly. I hope the answer will help you. Feel free to ask more questions.
Among the choices provided the answer should be letter C. Below is the solution:

top
pi r^2 or pi * 400 
sides 
2 pi r * 60 
40 * 60 pi 
2400pi 

so add the top and side we get p*400 + p*2400 = 2800 pi ft^2

6 0

3 years ago

Find the limit

Lana71 [14]

Step-by-step explanation:

<h3>Appropriate Question :-</h3>

Find the limit

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

$\large\underline{\sf{Solution-}}$

Given expression is

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

On substituting directly x = 1, we get,

$\rm \: = \: \sf \dfrac{1-2}{1 - 1}-\dfrac{1}{1 - 3 + 2}$

$\rm \: = \sf \: \: - \infty \: - \: \infty$

which is indeterminant form.

Consider again,

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right]$

can be rewritten as

$\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 3x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( {x}^{2} - 2x - x + 2)}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x( x(x - 2) - 1(x - 2))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x(x - 1)}-\dfrac{1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ {(x - 2)}^{2} - 1}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 2 - 1)(x - 2 + 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)(x - 1)}{x(x - 2) \: (x - 1))}\right]$

$\rm \: = \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{ (x - 3)}{x(x - 2)}\right]$

$\rm \: = \: \sf \: \dfrac{1 - 3}{1 \times (1 - 2)}$

$\rm \: = \: \sf \: \dfrac{ - 2}{ - 1}$

$\rm \: = \: \sf \boxed{2}$

Hence,

$\rm\implies \:\boxed{ \rm{ \:\rm \: \sf {\displaystyle{\lim_{x\to 1}}} \: \left[\dfrac{x-2}{x^2-x}-\dfrac{1}{x^3-3x^2+2x}\right] = 2 \: }}$

$\rule{190pt}{2pt}$

7 0

2 years ago

Read 2 more answers

Mai says that the equation 2x + 2 = x + 1 has no solution because the left-hand side is double the right hand side.

zhannawk [14.2K]

Answer:

h im billy

Step-by-step explanation:

7 0

2 years ago

Read 2 more answers

Another one Topic: Law of Indices Evaluate this; (13⁰÷5)²

Zarrin [17]

Answer:

Steps:

(13⁰/5)²

(1÷5)²

1²÷5²

1÷25

7 0

2 years ago

A surveyor holds a laser range finder 3 feet above the ground and determines that the range finder is 89 feet from a building an

Anna007 [38]

The distance to the top of the building above the range finder can be found from the Pythagorean theorem.
.. d = √(115² -89²) ≈ 72.8 . . . . feet

Adding the height of the range finder, we find the height of the building to be
.. h = d+3 = 75.8 ft

8 0

3 years ago