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2 years ago

How do I solve this problem?

Mathematics

1 answer:

Liono4ka [1.6K]2 years ago

3 0

Answer:

$10100$

Step-by-step explanation:

Use this formula,

$\frac{n}{2} (2 {a} + d(n - 1)$

where n is the amount of even intergers, a is the starting term, d is the common difference.

the amount of even intergers from 2 to 200 is 100
The starting number is 2
The common difference is 2

$\frac{100}{2} (4 + 2(99)$

$50(4 + 198)$

$50(202)$

$10100$

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Answer:

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Step-by-step explanation:

we know that

If two triangles are similar, then the ratio of its corresponding sides is proportional and its corresponding angles are congruent

<em>Triangle X.Y.Z</em>

$\angle X=61^o$

$\angle Z=90^o$

$\angle Y=90^o-61^o=29^o$ ---> angle X and angle Y are complementary angles

<em>Triangle H.G.J</em>

$\angle H=90^o-34^o=56^o$ ---> angle H and angle J are complementary angles

$\angle G=90^o$

$\angle J=34^o$

X.Y.Z is a $61^o-90^o-39^o$ triangle

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The measure of its corresponding angles are not congruent

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Answer:

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Answer:

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valina [46]

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Answer:

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