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Serjik [45]
2 years ago
14

How do I solve this problem?

Mathematics
1 answer:
Liono4ka [1.6K]2 years ago
3 0

Answer:

10100

Step-by-step explanation:

Use this formula,

\frac{n}{2} (2 {a} + d(n - 1)

where n is the amount of even intergers, a is the starting term, d is the common difference.

  • the amount of even intergers from 2 to 200 is 100
  • The starting number is 2
  • The common difference is 2

\frac{100}{2} (4 + 2(99)

50(4 + 198)

50(202)

10100

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Step-by-step explanation:

to have "roots" means that the function delivers 0 as function result for these values of x.

so,

f(x) = 0 for x = -2, x = 0 and x = 4

we can build this function as a product of factors.

each factor is an expression of x that turns 0 for the given value of x.

what is the simplest expression of x that turns 0, when x = -2 ?

well : x + 2

as you can easily see, this is 0, when x = -2.

and the easiest existing of x that is 0, when x = 0 ?

totally simple : just x.

and then x - 4 for x = 4

so, our function is

f(x) = x(x + 2)(x - 4)

but : this is one of infinite possibilities.

let's see what happens, if we use the x coordinate (-1) of the given point (-1, 10).

we know, the result must be 10.

-1×(-1 + 2)(-1 - 4) = -1×1×-5 = 5

aha ! so, in order to get 10 instead of just 5 we must multiply the whole thing by 2.

as n×0 is always still 0, this does not change our 0 points (or roots).

so, our full function is :

f(x) = 2x(x + 2)(x - 4)

or, if you need the function as a polynomial, we need to do the multiplications :

f(x) = 2x(x² - 4x + 2x - 8) = 2x(x² - 2x - 8) = 2x³ - 4x² - 16x

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Answer:

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