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3 years ago

Whats the solution to the system? the lines cross at (-1, 3)

Mathematics

1 answer:

Nata [24]3 years ago

3 0

Mmmmmmmmmmmmmm mmmmmmmmmmmmm

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Help find the missing lengths round to nearest tenth

Mama L [17]

Answer:

Step-by-step explanation:

Theta is 21 degrees

x is the adjacent side
8 is the opposite side
y is the hypothenuse

SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

$tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84$

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

$sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32$

6 0

3 years ago

Suppose a greeting card is 4 inches long on one side about how long should the other side of the card be in order for it to be g

Leviafan [203]

A triangle has 3 side, this makes no sense. Explain please.

4 0

4 years ago

Imagin math 40 points

EleoNora [17]

Answer:

sale price of video game

Step-by-step explanation:

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2 years ago

Simplify (12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})(12a 5 −6a−10a 3 )−(10a−2a 5 −14a 4 ) . Write the answer in standard form

Katen [24]

Answer:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

Step-by-step explanation:

Given

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Required

Simplify

We have:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4})$

Open brackets

$12a^{5}-6a-10a^{3}-10a+2a^{5}+14a^{4}$

Collect like terms

$12a^{5}+2a^{5}+14a^{4}-10a^{3}-6a-10a$

$14a^{5}+14a^{4}-10a^{3}-16a$

Hence:

$(12a^{5}-6a-10a^{3})-(10a-2a^{5}-14a^{4}) = 14a^{5}+14a^{4}-10a^{3}-16a$

6 0

3 years ago

Bill can mow a lawn in 40min and jhon can mow for 60min.how long will it take to mow together

valentinak56 [21]

24 minutes.

Let me explain.

The lawn can be any size, but for the purpose of simplicity, let's say it's 240 square meters.

Peter mows 6 square meters per minute if he mows 240 square meters in 40 minutes.

John mows 4 square metres each minute if he mows 240 square metres in 60 minutes.

They'll mow 10 square meters per minute if they work together.

As a result, mowing the entire lawn will take them 24 minutes.

(Note that the location is irrelevant as long as we know how long each man takes to complete the task separately.) The answer would be the same if the field was 1 million hectares in size.)

I hope this helps.

3 0

2 years ago