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3 years ago

Help find the missing lengths round to nearest tenth

Mathematics

1 answer:

Mama L [17]3 years ago

6 0

Answer:

Step-by-step explanation:

Theta is 21 degrees

x is the adjacent side
8 is the opposite side
y is the hypothenuse

SOH - CAH - TOA

Since the opposite side is given and we need to find the length of the adjacent side, we can use tangent to solve for x.

$tan 21=\frac{opposite}{adjacent} \\tan 21 =\frac{8}{x} \\0.384 =\frac{8}{x} \\0.384x =8 \\x=\frac{8}{0.384} \\x=20.84$

Since the opposite side is given and we need to find the length of the hypotenuse, we can use sine to solve for y.

$sin 21=\frac{opposite}{hypotenuse} \\sin21 =\frac{8}{y} \\0.358 =\frac{8}{y} \\0.358y=8 \\y=\frac{8}{0.358} \\y=22.32$

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Part A: Look at the graph! The highest y-value should be the maximum of each graph, which can be located at the vertex of a quadratic function. In this graph, the vertex is (2.5, 2531.25), where which its y-value contains the highest point of a graph, since the graph is concave down.

$y=a(x-2.5)^{2} +2531.25\\$

$0=a(25-2.5)^{2} +2531.25\\$

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$y=-5(x-2.5) ^{2}+2531.25$

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