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GalinKa [24]
3 years ago
5

Benjamin needs $0.75 more cents to buy a granola bar that costs $1.89. How much money does Benjamin have now?

Mathematics
1 answer:
Elden [556K]3 years ago
4 0
The answer is $1.14. If the granola bar costs $1.89 but he is missing the .75 then you need to just subtract the .75 from the $1.89.

The calculation is: $1.89 - .75 = $1.14.
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The distribution of the scores on a certain exam is ​N(40​,5​), which means that the exam scores are Normally distributed with a
katen-ka-za [31]

Answer:

Step-by-step explanation:

Let x represent the random variable representing the scores in the exam. Given that the scores are normally distributed with a mean of 40 and a standard deviation of 5, the diagram representing the curve and​ the position of the​ mean, the mean plus or minus one standard​ deviation, the mean plus or minus two standard​ deviations, and the mean plus or minus three standard deviations is shown in the attached photo

1 standard deviation = 5

2 standard deviations = 2 × 5 = 10

3 standard deviations = 3 × 5 = 15

1 standard deviation from the mean lies between (40 - 5) and (40 + 5)

2 standard deviations from the mean lies between (40 - 10) and (40 + 10)

3 standard deviations from the mean lies between (40 - 15) and (40 + 15)

b) We would apply the probability for normal distribution which is expressed as

z = (x - µ)/σ

Where

x = sample mean

µ = population mean

σ = standard deviation

From the information given,

µ = 40

σ = 5

the probability that a randomly selected score will be greater than 50 is expressed as

P(x > 50) = 1 - P( ≤ x 50)

For x = 50,

z = (50 - 40)/5 = 2

Looking at the normal distribution table, the probability corresponding to the z score is 0.98

P(x > 50) = 1 - 0.98 = 0.02

7 0
3 years ago
after flying at an altitude of 50 meters, a helicopter starts to descend when its ground distance from the landing pad is 11 kil
yarga [219]

Answer:

The angle of depression for the flight part is approximately 0.2604 degrees

Step-by-step explanation:

The given altitude at which the helicopter is flying = 50 meters

The horizontal distance of the helicopter from the helipad = 11 kilometers = 11,000 meters

The angle of depression = The angle of elevation = Arctan(Altitude/(Horizontal distance)

Therefore;

The angle of depression for the flight part = Arctan(50/(11,000)) ≈ 0.2604 degrees

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3 years ago
among the 2287 respondents, 500 said that they only play hockey. what fraction of respondents said they only play hockey?
Jet001 [13]

Answer:

5

Step-by-step explanation:

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3 years ago
Allen has a photo that is 6 in by 8 in. What will the dimensions of the photo be if he scales it down by a factor of ? (5 points
Irina18 [472]

Answer:

It will be 3 in by 4 in

Step-by-step explanation:

Original dimension is 6 in by 8 in

If he scale it down by a factor of 1/2

The new dimension will be

1/2(6) by 1/2(8)

= 3 by 4

= 3 in by 4 in

7 0
3 years ago
What is the expansion of (3+x)^4
Vlad1618 [11]

Answer:

\left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81

Step-by-step explanation:

Considering the expression

\left(3+x\right)^4

Lets determine the expansion of the expression

\left(3+x\right)^4

\mathrm{Apply\:binomial\:theorem}:\quad \left(a+b\right)^n=\sum _{i=0}^n\binom{n}{i}a^{\left(n-i\right)}b^i

a=3,\:\:b=x

=\sum _{i=0}^4\binom{4}{i}\cdot \:3^{\left(4-i\right)}x^i

Expanding summation

\binom{n}{i}=\frac{n!}{i!\left(n-i\right)!}

i=0\quad :\quad \frac{4!}{0!\left(4-0\right)!}3^4x^0

i=1\quad :\quad \frac{4!}{1!\left(4-1\right)!}3^3x^1

i=2\quad :\quad \frac{4!}{2!\left(4-2\right)!}3^2x^2

i=3\quad :\quad \frac{4!}{3!\left(4-3\right)!}3^1x^3

i=4\quad :\quad \frac{4!}{4!\left(4-4\right)!}3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

=\frac{4!}{0!\left(4-0\right)!}\cdot \:3^4x^0+\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1+\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2+\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3+\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4

as

\frac{4!}{0!\left(4-0\right)!}\cdot \:\:3^4x^0:\:\:\:\:\:\:81

\frac{4!}{1!\left(4-1\right)!}\cdot \:3^3x^1:\quad 108x

\frac{4!}{2!\left(4-2\right)!}\cdot \:3^2x^2:\quad 54x^2

\frac{4!}{3!\left(4-3\right)!}\cdot \:3^1x^3:\quad 12x^3

\frac{4!}{4!\left(4-4\right)!}\cdot \:3^0x^4:\quad x^4

so equation becomes

=81+108x+54x^2+12x^3+x^4

=x^4+12x^3+54x^2+108x+81

Therefore,

  • \left(3+x\right)^4:\quad x^4+12x^3+54x^2+108x+81
6 0
4 years ago
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