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ziro4ka [17]
3 years ago
6

Helpppp thanks in advance

Mathematics
1 answer:
CaHeK987 [17]3 years ago
4 0

Answer:

Lets mark the unmarked angle as angle A and the base of the building as BC

We can use tan to find this

tan=opposite/adjacent

by knowing the 2 interior angles we can calculate the measure of A sicne the interior angles of any triangle add up to 180

52+90+A=180

142+a=180

38=a

tan(38)=BC/300

300 tan(38)=bc

using a calculator we see that bc=234.385689 or 234meters rounded

Step-by-step explanation:

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Answer:

y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}

Step-by-step explanation:

Given

y=c_1e^x +c_2e^{-x

y(1) = 0

y'(1) =e

Required

The solution

Differentiate y=c_1e^x +c_2e^{-x

y' = c_1e^x - c_2e^{-x}

Next, we solve for c1 and c2

y(1) = 0 implies that; x = 1 and y = 0

So, we have:

y=c_1e^x +c_2e^{-x

0 = c_1 * e^1 + c_2 * e^{-1}

0 = c_1 e + \frac{1}{e}c_2 --- (1)

y'(1) =e implies that: x = 1 and y' = e

So, we have:

y' = c_1e^x - c_2e^{-x}

e = c_1 * e^1 - c_2 * e^{-1}

e = c_1 e - \frac{1}{e}c_2 --- (2)

Add (1) and (2)

0 + e = c_1e + c_1e + \frac{1}{e}c_2 - \frac{1}{e}c_2

e = 2c_1e

Divide both sided by e

1 = 2c_1

Divide both sides by 2

c_1 = \frac{1}{2}

Substitute c_1 = \frac{1}{2} in 0 = c_1 e + \frac{1}{e}c_2

0 = \frac{1}{2} e+ \frac{1}{e}c_2

Rewrite as:

\frac{1}{e}c_2 = -\frac{1}{2} e

Multiply both sides by e

c_2 = -\frac{1}{2} e^2

So, we have:

y=c_1e^x +c_2e^{-x

y = \frac{1}{2}e^x -\frac{1}{2} e^2 * e^{-x}

y = \frac{1}{2}e^x -\frac{1}{2} e^{2-x}

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36 = 4*9  = 2*2 *3*3

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Store A uses the newsvendor model to manage its inventory. Demand for its product is normally distributed with a mean of 500 and
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Answer:

P(X

Step-by-step explanation:

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".  

The Z-score is "a numerical measurement used in statistics of a value's relationship to the mean (average) of a group of values, measured in terms of standard deviations from the mean".  

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And let \bar X represent the sample mean, the distribution for the sample mean is given by:  

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What is its in-stock probability if Store A’s order quantity is 800 units?

We are looking for this probability:

What is its in-stock probability if Store A’s order quantity is 800 units?

So we can find the following values:

P(X>800) and P(X

Sor this problem we can use the z score formula given by:

z=\frac{x-\mu}{\sigma}

If we find the z score for the value 800 we got:

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P(X

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