Answer:
Option D. y = 5x + 1
Step-by-step explanation:
From the question given above, the following data were:
Input (x) >>>>>> Output (y)
0 >>>>>>>>>>>> 1
1 >>>>>>>>>>>> 6
2 >>>>>>>>>>>> 11
3 >>>>>>>>>>>> 16
4 >>>>>>>>>>>> 21
To know the the correct answer to the question, we shall apply the equation given in each option to see which will satisfy the table. This can be obtained as follow:
For Option a
y = 3x + 3
x = 0
y = 3(0) + 3
y = 0 + 3
y = 0
y = 3x + 3
x = 1
y = 3(1) + 3
y = 3 + 3
y = 6
For Option b
y = 5x – 4
x = 0
y = 5(0) – 4
y = 0 – 4
y = – 4
y = 5x – 4
x = 1
y = 5(1) – 4
y = 5 – 4
y = 1
For Option c
y = 10x – 9
x = 0
y = 10(0) – 9
y = 0 – 9
y = – 9
y = 10x – 9
x = 1
y = 10(1) – 9
y = 10 – 9
y = 1
For Option d
y = 5x + 1
x = 0
y = 5(0) + 1
y = 0 + 1
y = 1
y = 5x + 1
x = 1
y = 5(1) + 1
y = 5 + 1
y = 6
From the illustrations made above, only option d satisfy the table. Thus, option d gives the correct answer to the question.
8 rock in 5 minutes
54 rocks / 8 rocks = 6.75
6.75 x 5 minutes = 33.75 minutes
RS Bisects QT means, it cuts QT in two equal halves, so QP would be equal to PT, as it is an isosceles triangle, one other side would be equal as well, so RP is equal to PS, Now, by ASA, we conclude the both mentioned triangles in the figure are congruent.
Hope this helps!
(a) From the histogram, you can see that there are 2 students with scores between 50 and 60; 3 between 60 and 70; 7 between 70 and 80; 9 between 80 and 90; and 1 between 90 and 100. So there are a total of 2 + 3 + 7 + 9 + 1 = 22 students.
(b) This is entirely up to whoever constructed the histogram to begin with... It's ambiguous as to which of the groups contains students with a score of exactly 60 - are they placed in the 50-60 group, or in the 60-70 group?
On the other hand, if a student gets a score of 100, then they would certainly be put in the 90-100 group. So for the sake of consistency, you should probably assume that the groups are assigned as follows:
50 ≤ score ≤ 60 ==> 50-60
60 < score ≤ 70 ==> 60-70
70 < score ≤ 80 ==> 70-80
80 < score ≤ 90 ==> 80-90
90 < score ≤ 100 ==> 90-100
Then a student who scored a 60 should be added to the 50-60 category.
Box Plot has less variability in the data. We can determine this by the distances between the beginning of the data to the end (range) and the distances between lower quartile and the upper quartile (interquartile range).
Box #1
Range - 30
IQR - 15
Box #2
Range - approximately 23
IQR - approximately 9
Box #2 has less variation in the data because the distances between these 2 ranges are smaller meaning the data is closer together.
