<span><span><span>10<span>(<span>1−23</span>)</span></span><span>(2)</span></span>+13</span><span>=<span><span><span><span>(10)</span><span>(<span>−22</span>)</span></span><span>(2)</span></span>+13</span></span><span>=<span><span><span>(<span>−220</span>)</span><span>(2)</span></span>+13</span></span><span>=<span><span>−440</span>+13</span></span><span>=<span>−<span>427</span></span></span>
Answer:
Good. I don't like the school that is a part of the day but other than that life is awesome.
Step-by-step explanation:
Since 
and 
, we have
So, the equation becomes
The solutions to this equation are 4 and -5/2, so I'm afraid there's a typo in your question.
Answer:
The answer is given below
Step-by-step explanation:
The loads in the circuit are continuous duty, so the circuit can only loaded to 80% of its current rating.
Calculate 80% current rating of the circuit breaker.
Icb = [ 80/100] (20 A)
= (O.8) (20 A )
= 16 A
Now we assume that the value of supply voltage is 120 V
Now we will calculate current flows via under water light which will be taken as Load 1
<em>Ii = </em>500 W/120 V
= 4.167 A
Current via the circulating pump which will be taken as Load 2 IS 8.5 A
<em>I = </em>load1 + load 2
<em> = 4.167 A + 8.5 A</em>
<em> = 12.67 A</em>
The total current in the circuit obtained which is less than the circuit breaker rating current. Therefore, the power can be operated for both the loads.
