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Varvara68 [4.7K]
3 years ago
13

ELICIT/ENGAGE

Chemistry
1 answer:
UNO [17]3 years ago
3 0

Answer:

where's the picture of the car?

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Why is the answer C for this problem?
pshichka [43]

Answer:

\boxed{\text{(C) X}$_{3}$P$_{2}}

Explanation:

Step 1. Identify the Group that contains X

We look at the consecutive ionization energies and hunt for a big jump between them

\begin{array}{crc}n & IE_{n} & IE_{n} - IE_{n-1}\\1 & 730 & \\2 & 1450 & 720\\3 & 7700 & 6250\\4 & 10500 & 2800\\\end{array}

We see a big jump between n = 2 and n = 3. This indicates that X has two valence electrons.

We can easily remove two electrons, but the third electron requires much more energy. That electron must be in the stable, filled, inner core.

So, X is in Group 2 and P is in Group 15.

Step 2. Identify the Compound

X can lose two valence electrons to reach a stable octet, and P can do the same by gaining three electrons.

We must have 3 X atoms for every 2 P atoms.

The formula of the compound is \boxed{\text{X}$_{3}$P$_{2}}$}.

4 0
3 years ago
How many moles are in 117.30 grams of KCLO3?
eduard

0.0081599680129254

Hope this helps?

5 0
3 years ago
Which of the following best defines Avogadro's number? (5 points)
Likurg_2 [28]

Answer:

Avogadro's number is 6.022* 10^23

3 0
3 years ago
Read 2 more answers
At constant temperature and pressure, increasing the amount of a gas will __________.
aivan3 [116]
At constant temperature and pressure, increasing the amount of gas will increase the volume.
6 0
3 years ago
Gasoline has an octane number of 70.
mariarad [96]
Best Answer: o.n. = 70 means 70% isoctane for which o.n. = 100 and 30% of heptane for which o.n. = 0
5 0
4 years ago
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