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luda_lava [24]
3 years ago
6

Select the correct answer from each dropdown menu. in the figure, the radius of the partial circle with center A is 4 feet.

Mathematics
2 answers:
charle [14.2K]3 years ago
6 0

Answer:24.50 and 46.68

Step-by-step explanation:

I took the test

Alika [10]3 years ago
4 0

Answer:

Step-by-step explanation:

Part A: 24.50 feet, Part B: 46.68 square feet, I just took the test and got this right!

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4 years ago
If cot theta= 4/3, find csc theta
Marrrta [24]

Answer: Option d.

Step-by-step explanation:

The trigonometric identity needed is:

csc^2\theta=cot^2\theta+1

Knowing that cot\theta=\frac{4}{3}:

Substitute it into csc^2\theta=cot^2\theta+1:

csc^2\theta=(\frac{4}{3})^2+1

Simplify the expression:

csc^2\theta=(\frac{4}{3})^2+1\\\\csc^2\theta=\frac{16}{9}+1\\\\csc^2\theta=\frac{25}{9}

Solve for csc\theta. Apply square root at both sides of the expression:

\sqrt{csc^2\theta}=\±\sqrt{\frac{25}{9}}

csc\theta=\frac{5}{3}

8 0
3 years ago
(10 pts) (a) (2 pts) What is the difference between an ordinary differential equation and an initial value problem? (b) (2 pts)
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Answer:

Step-by-step explanation:

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(B) The difference between a particular solution and a general solution to an equation is that a particular solution is any specific figure that can satisfy the equation while a general solution is a statement that comprises all particular solutions of the equation.

(C) Example of a second order linear ODE:

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The equation will be homogeneous if K(t)=0 and heterogeneous if K(t)\neq 0

Example of a second order nonlinear ODE:

Y=-3K(Y){2}

(D) Example of a nonlinear fourth order ODE:

K^4(x) - \beta f [x, k(x)] = 0

4 0
4 years ago
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MAVERICK [17]

Answer:

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Step-by-step explanation:

8 0
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Slope is rise over run. Go up 1 unit, right 4 units to get to the next point.
the slope is 1/4
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4 years ago
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