For this case we have the following function:
y = 9 (3) ^ x
Applying the following transformations we have:
Horizontal translations
Suppose that h> 0
To graph y = f (x-h), move the graph of h units to the right.
y = 9 (3) ^ (x-2)
Vertical translations
Suppose that k> 0
To graph y = f (x) -k, move the graph of k units down.
y = 9 (3) ^ (x-2) - 6
Answer:
2 units to the right
6 units down
Answer:
x = 11.75
y = 11.5
Step-by-step explanation:
By Elimination Method:
7x - 3y = 48 ---- (1)
-
<u> 2x + y = 35 ----</u>- (2)
Multiply equation (1) by 2 and equation (2) by 7
14x - 6y = 96
-
<u> 14x + 7y = 245 </u>
<u> 0 -13y = -149</u>
-13y = -149
y = -149/-13
y = 11.5
From equation (2); replace y with 12
2x + y = 35
2x + 11.5 = 35
2x = 35 - 11.5
2x = 23.5
x = 11.75
D + t = total earnings
$3h + t = total earnings
$3h + $22 = total earnings
Fill in h as however many hours she is working.
Example: She worked for 8 hrs and got $22 in tips.
$3(8) + $22 = ?
$24 +$22 = $46
Answer:
if this is your ans then happy to help
Given
centre of circle O(3,2)=O(x0,y0)
point on circle P(6,-2)
Standard equation of circle:
(x-x0)^2+(y-y0)^2=r^2
r=radius of circle
= (distance OP)
= sqrt((6-3)^2+(-2-2)^2)
=sqrt(3^2+(-4)^2)
=sqrt(25)
=>
r^2=(sqrt(25))^2=25
Equation of circle
(x-x0)^2+(y-y0)^2=r^2
(x-3)^2+(y-2)^2=25 ............... standard equation of circle
