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aalyn [17]
3 years ago
7

Answer this question please than you now by tody

Mathematics
1 answer:
kolbaska11 [484]3 years ago
8 0

Answer:

the answer is line RQ and line OP

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Find the product for these questions  1.( 2x ) ( 10x ) 2.  -3m( m + 8 ) 3. 4d( 2d -9 ) 4. ( 3x + 4 ) ( x -2 ) 5. ( 2y -1 ) ( 4y
Salsk061 [2.6K]
 1.( 2x ) ( 10x ) = 20 x²

2.  -3m( m + 8 ) = -3m² - 24m

3. 4d( 2d -9 ) = 8d² - 36d

4. ( 3x + 4 ) ( x -2 ) = 3x² - 6x + 4x - 8 = 3x² - 2x -8
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5. ( 2y -1 ) ( 4y - 3 ) = 8y</span>² - 6y - 4y + 3 = 8y² -10y +3
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3 years ago
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5.

Let x be the age of the father and y be the age of the son. As of today, he's 3 times older, so we have x=3y

10 years ago their ages were, respectively, x-10 and y-10, and the father was 5 times older: x-10 = 5(y-10)

So, we have the system

\begin{cases} x=3y\\x-10=5(y-10)\end{cases}

Using the first equation, we can substitute every occurrence of "x" with "3y" in the second equation:

3y-10=5(y-10) \iff 3y-10=5y-50 \iff 2y = 40 \iff y=20

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Indeed, 10 years ago they were 10 and 50 years old, so the father was 5 times older.

6.

Let x be the age of the grandfather and y the age of the granddaughter. We know that the grandfather is 10 times older: x=10y

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Step-by-step explanation:

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Step-by-step explanation:

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4 years ago
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Step-by-step explanation:

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