(04.02 MC)
1 answer:
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Given:
The given equation is
To find:
All the real solutions.
Solution:
We have,
It can be written as
Using zero product property, we get
and
and
and
We know that is an imaginary number because there is a negative sign under the square root.
Therefore, is the only real solution of the given equation.
You can find the remainder right away by simply plugging in 
. The polynomial remainder theorem guarantees that the value of 
is the remainder upon dividing 
by 
, but I digress...
Synthetic division yields
3 | 2 -11 18 -15
. | 6 -15 9
- - - - - - - - - - - - - - - - -
. | 2 -5 3 -6
which translates to
(and note that
, as expected)
Synthetic division yields
3 | 2 -11 18 -15
. | 6 -15 9
- - - - - - - - - - - - - - - - -
. | 2 -5 3 -6
which translates to
(and note that