Answer:
4 Blue chips
6 Yellow chips
10 Red chips
Imagine 20% as 2 of 10. We have 20 chips, and that's double of that. So if we have 2/10... we will have 4/20
Same with the yellow chips. Imagine 30% as 3 of 10, again double that... 6/20.
It doesn't directly say the percent of design a computer representation but we can infer that if we have 20% and 30%... that makes 50%, there is only 100 in a percent, so that means there is 50% left! We repeat the process where we envision 50% as 5 of 10, double that. Now we have 10 of 20, 50%!
(a) Yes all six trig functions exist for this point in quadrant III. The only time you'll run into problems is when either x = 0 or y = 0, due to division by zero errors. For instance, if x = 0, then tan(t) = sin(t)/cos(t) will have cos(t) = 0, as x = cos(t). you cannot have zero in the denominator. Since neither coordinate is zero, we don't have such problems.
---------------------------------------------------------------------------------------
(b) The following functions are positive in quadrant III:
tangent, cotangent
The following functions are negative in quadrant III
cosine, sine, secant, cosecant
A short explanation is that x = cos(t) and y = sin(t). The x and y coordinates are negative in quadrant III, so both sine and cosine are negative. Their reciprocal functions secant and cosecant are negative here as well. Combining sine and cosine to get tan = sin/cos, we see that the negatives cancel which is why tangent is positive here. Cotangent is also positive for similar reasons.
Answer:3/5
Step-by-step explanation: and if you have trouble understanding slope again just do rise over run. Good luck :)
Answer:
The probability that x will take on a value between 120 and 125 is 0.14145
Step-by-step explanation:
For uniform distribution between a & b
Mean, xbar = (a + b)/2
Standard deviation, σ = √((b-a)²/12)
For 110 and 150,
Mean, xbar = (150 + 110)/2 = 130
Standard deviation, σ = √((150-110)²/12 = 11.55
To find the probability that x will take on a value between 120 and 125
We need to standardize 120 & 125
z = (x - xbar)/σ = (120 - 130)/11.55 = - 0.87
z = (x - xbar)/σ = (125 - 130)/11.55 = - 0.43
P(120 < x < 125) = P(-0.87 < x < -0.43)
We'll use data from the normal probability table for these probabilities
P(120 < x < 125) = P(-0.87 < x < -0.43) = P(z ≤ -0.43) - P(z ≤ -0.86) = 0.33360 - 0.19215 = 0.14145
Hope this Helps!!!
Answer:
Simplify
A ⋅ 13−oz.
−oz+13 A
Simplify
a⋅20+0z.
20a
List all of the solutions.
A⋅13−oz=−oz+13A 78=−oz+13a⋅20
