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lesantik [10]
3 years ago
11

What is the distance between the points (5, 13) and (-8, -9) on a coordinate plane rounded to the nearest tenth unit?

Mathematics
1 answer:
insens350 [35]3 years ago
8 0

Answer:

25.6

Step-by-step explanation:

Use the distance formula.

d = \sqrt{(x_2 - x_1)^2 + (y_2-y_1)^2}\\d = \sqrt{(-8 - 5)^2 + (-9-13)^2}\\d = \sqrt{(-13)^2 + (-22)^2}\\d = \sqrt{169 + 484}\\d = \sqrt{653}

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marshall27 [118]

43/76

This is the answer

3 0
3 years ago
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Suppose that you are headed toward a plataeu 70m high. If the angle of elevation to the top of the platau is 35 degree how far a
SIZIF [17.4K]

Answer:

The distance you are from the base of plateau = 99.97\ m\approx 100\ m

Step-by-step explanation:

Given:

Height of plateau = 70 m

Angle of elevation to the top of plateau = 35°

To find the distance you are from the base of plateau.

We will construct a triangle ABC to model the given situation. The triangle would be a right triangle for which we know an angle and its opposite side. We need to find the adjacent side of the triangle.

We will apply trigonometric ratio to find the adjacent side.

\tan\theta=\frac{Opposite\ Side}{Adjacent\ Side}

where \theta represents the angle of reference.

Plugging in the values from the triangle.

\tan 35\° =\frac{BC}{AC}

\tan 35\° =\frac{70}{AC}

Multiplying both sides by AC.

AC\times \tan 35\° =AC\times \frac{70}{AC}

AC\times \tan 35\° =70

Dividing both sides by \tan 35\°

\frac{AC\times \tan 35\°}{\tan 35\°} =\frac{70}{\tan 35\°}

∴ AC=99.97\ m\approx 100\ m

The distance you are from the base of plateau = 99.97\ m\approx 100\ m

7 0
3 years ago
Which polynomial is a perfect square trinomal x^2 -6x +9 b) x^2 -2x +4 c) x^2 +5x +10 d) x^2 +4x +16
cestrela7 [59]
I hope this helps you

3 0
3 years ago
I need help for my hw asap!! Help pls!!! Thank you
djyliett [7]

Answer:

1. S.A. = 4350 cm²

2. S.A. = 864 cm²

3. S.A. = 240 cm²

4. S.A. = 224 m²

5. S.A. = 301.6 in.²

6. S.A. = 6,082.1 cm²

7. S.A. = 923.6 in.²

Step-by-step explanation:

1. Surface area of the rectangular prism = 2(LW + LH + WH)

L = 45 cm

W = 25 cm

H = 15 cm

S.A. = 2(45*25 + 45*15 + 25*15)

S.A. = 4350 m²

2. Surface area of the cube = 6a²

a = 12 cm

S.A. = 6(12²)

S.A. = 864 cm²

3. Surface area of triangular prism = bh + (s1 + s2 + s3)*H

b = 4 cm

h = 6 cm

s1 = 4 cm

s2 = 7 cm

s3 = 7 cm

H = 12 cm

Plug in the values

S.A. = 4*6 + (4 + 7 + 7)*12

S.A. = 24 + (18)*12

S.A. = 24 + 216

S.A. = 240 cm²

4. Surface area of the square based pyramid = area of the square base + 4(area of 1 triangular face)

S.A. = (8*8) + 4[(8*10)/2]

S.A. = 64 + 4(40)

S.A. = 64 + 160

S.A. = 224 cm²

5. Surface area of the cone = πrl + πr²

r = 6 in.

l = 10 in.

S.A. = π*6*10 + π*r²

S.A. = 60π + 36π

S.A. = 301.592895

S.A. = 301.6 in.² (nearest tenth)

6. Surface area of the sphere = 4πr²

r = 22 cm

S.A. = 4*π*22²

S.A. = 1,936π

S.A. = 6,082.1 cm² (nearest tenth)

7. Surface area of the cylinder = 2πrh + 2πr²

r = 7 in.

h = 14 in.

S.A. = 2*π*7*14 + 2*π*7²

S.A. = 923.6 in.² (nearest tenth)

3 0
3 years ago
Write the equation of the line perpendicular to y=2/3 x−12 that passes through the point (4, -1) in slope-intercept form.
xenn [34]

Answer:

Step-by-step explanation:

perp. -3/2

y + 1 = -3/2(x - 4)

y + 1 = -3/2x + 6

y = -3/2x + 5

7 0
3 years ago
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