Answer:
honestly,I also really didn't know the ans so I took it from internet. hope you won't mind
H(t)=-16t^2+96+256. What is the initial value
2 answers:
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Answer:
no horizontal asymptote
Step-by-step explanation:
When the degree of the numerator > degree of the denominator there is no horizontal asymptote but there is a slant asymptote.
Dividing the numerator by the denominator gives
= x - 5 +
There is a slant asymptote with equation y = x - 5