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AysviL [449]
3 years ago
8

Find the first partial derivatives of the function. f(x, y) = ax + by/ cx + dy

Mathematics
1 answer:
Marina86 [1]3 years ago
5 0
<span>The partial derivative of the given function with respect to x is a - by/cx2 + dy/dx In this derivative the terms in the with x is only considered other or treated as constant The partial derivative of the given function with respect to y is b/cx+ d2y/dx. In this derivative the terms in the with x is only considered other or treated as constant</span>
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Tristan is comparing two number patterns based on the information below. Both patterns start with the number 1. Pattern A follow
Oksana_A [137]

Answer:

  Pattern B gets larger faster.

Step-by-step explanation:

Pattern A: 1, 4, 7, 10, 13

Pattern B: 1, 5, 9, 13, 17

The terms of pattern B are larger than those of Pattern A by 1 less than the number of the term. (Term 5 of Pattern B is 4 more than term 5 of Pattern A, for example.)

4 0
3 years ago
Alice stand at point A and looks at the top of a 17.8 m tree TB, such that her line of sight makes an angle 38° with the horizon
Nesterboy [21]

Answer:

Step-by-step explanation:

let the horizontal distance be x

(17.8-1.5)/x = tan 38

or x = 16.3/tan38

or x = 20.863

4 0
2 years ago
Which answer BEST describes the solution for x if – 3 &lt; x + 4 ≤ 7?
Mama L [17]
C is the answer look at the way I. form is
8 0
3 years ago
Read 2 more answers
A summer camp had
trapecia [35]

The equation that relates the number of campers this year to the number of campers last year is c = 440 / 1.10

The number of campers last year is 400.

<h3>What are percentages?</h3>

Percentage can be described as a fraction out of an amount that is usually expressed as a number out of hundred. Percentages are used to measure frequency.

<h3>How many campers attended last year?</h3>

The number of campers last year = number of campers this year / (1 + percentage increase)

440 / 1.1 = 400

To learn more about percentages, please check: brainly.com/question/25764815

3 0
2 years ago
In the Salk vaccine field trial, 400,000 children were part of a randomized controlled double-blind experiment. Just about half
EastWind [94]

Answer:

Step-by-step explanation:

From the given information:

The number of children that were randomly allocated to each vaccination group; n₁ = 200,000

No of polio cases X₁ = 57

Now, in the vaccine group:

the proportion of polio cases is:

\hat p_1 = \dfrac{57}{200000}

=  0.000285

The number of children that were randomly allocated to the placebo group, n₂ = 200,000

No of polio cases X₂ = 142

In the placebo group

the proportion of polio cases is:

\hat p_2 = \dfrac{142}{200000}

Null and alternative hypothesis is computed as follows:

H₀: There is no difference in the proportions of polio cases between both groups.  

H₁: There is a difference in the proportions of polio cases between both groups.

Let assume that the level of significance ∝ = 0.05

The test statistic  can be computed as:

Z = \dfrac{\hat p_1-\hat p_2}{\sqrt{\dfrac{\hat p_1 \hat q_1}{n_1}+ \dfrac{\hat p_2 \hat q_2}{n_2}}}

Z = \dfrac{0.000285-0.000710}{\sqrt{\dfrac{0.000285(1-0.000285)}{200000}+ \dfrac{0.000710(1-0.000710)}{200000}}}

Z = \dfrac{-4.25\times 10^{-4}}{\sqrt{\dfrac{0.000285(0.999715)}{200000}+ \dfrac{0.000710(0.99929)}{200000}}}

Z = - 6.03

P-value =  2P(Z < -6.03)

From the Z - tables

P-value =  2 × 0.0000

= 0.000

We reject the H₀ provided that P-value is very less.

Therefore, we may conclude that there is a difference in the proportions of polio cases between the vaccine group and placebo group not due to chance.

7 0
2 years ago
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