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alekssr [168]
3 years ago
12

WILL MARK BRAINLIEST

Chemistry
2 answers:
Dovator [93]3 years ago
4 0

Answer:

simple machine

Explanation:

A seesaw is a simple machine, which just sways back and forth.

A complex machine is like a roller-coaster, or any other carnival game.

A mechanical machine has many screws, and is run by a human with a remote or something else.

The answer to the question has to be simple machine. Hope this helps!

Afina-wow [57]3 years ago
4 0

Answer:

simple machine

Explanation: I took the test on k12

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CVOPEDIA-CVOSOFT

Explanation:

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Use the drop-down menus to identify each organic reaction as an addition, substitution, elimination, or condensation reaction. (
Bezzdna [24]

A chemical reaction involves an interaction between two or more species to yield a product.

<h3>What is a chemical reaction?</h3>

A chemical reaction involves an interaction between two or more species to yield a product.

The following is the classification of the reactions based on type;

  • The first reaction shown in the attachment is a condensation reaction
  • The second reaction is an addition reaction
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Learn more about reaction:brainly.com/question/9524025

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3 0
3 years ago
The atomic masses of 151eu and 153eu are 150.919860 and 152.921243 amu, respectively. The average atomic mass of europium is 151
vitfil [10]

Answer:-  The natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .

Solution:- Average atomic mass of an element is calculated from the atomic masses of it's isotopes and their abundances using the formula:

Average atomic mass = mass of first isotope(abundance) + mass of second isotope(abundance)

We have been given with atomic masses for ^1^5^1_E_u and ^1^5^3_E_u as 150.919860 and 152.921243 amu, respectively.  Average atomic mass of Eu is 151.964 amu.

Sum of natural abundances of isotopes of an element is always 1. If we assume the abundance of ^1^5^1_E_u as n then the abundance of ^1^5^3_E_u would be 1-n .

Let's plug in the values in the formula:

151.964=150.919860(n)+152.921243(1-n)

151.964=150.919860n+152.921243-152.921243n

on keeping similar terms on same side:

151.964-152.921243=150.919860n-152.921243n

-0.957243=-2.001383n

negative sign is on both sides so it is canceled:

0.957243=2.001383n

n=\frac{0.957243}{2.001383}

n=0.478

The abundance of ^1^5^1_E_u is 0.478 which is 47.8%.  

The abundance of ^1^5^3_E_u is = 1-0.478

= 0.522 which is 52.2%

Hence, the natural abundance of ^1^5^1_E_u is 0.478 or 47.8% and ^1^5^3_E_u is 0.522 or 52.2% .


3 0
3 years ago
A balloon occupies 1.50 L with 0.205 mol of carbon dioxide. How many moles would be required to increase the size of the balloon
Gekata [30.6K]

Answer:

0.683 moles of the gas are required

Explanation:

Avogadro's law relates the moles of a gas with its volume. The volume of a gas is directely proportional to its moles when temperature and pressure of the gas remains constant. The law is:

V₁n₂ = V₂n₁

<em>Where V is volume and n are moles of 1, initial state and 2, final state of the gas.</em>

<em />

Computing the values of the problem:

1.50Ln₂ = 5L*0.205mol

n₂ = 0.683 moles of the gas are required

<em />

8 0
3 years ago
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