Answer:
=final temperature
Explanation:
In the question specific heat of water is not given but we should know the value of that and it 4.18Jg∘C
Specific heat means how much heat is required to increase the temperature of 1 gram of substance that substance by 1∘C .
Equation between heat lost or gain and the change in temperature.
q=m⋅c⋅ΔT , where
q - the amount of heat
m - the mass of the sample
c - specific heat of sample
ΔT - change in temperature
put all the given value into this ,
=final temperature.
Answer: it they are both in the same place
Explanation:I don’t know and don’t care loser
Answer:
0.03g/mL
Explanation:
Given parameters include:
Five μL of a 10-to-1 dilution of a sample; This implies the Volume of dilute sample is given as 5 μL
Dilution factor = 10-to-1
The absorbance at 595 nm was 0.78
Mass of the diluted sample = 0.015 mg
We need to first determine the concentration of the diluted sample which is required in calculating the protein concentration of the original solution.
So, to determine the concentration of the diluted sample, we have:
concentration of diluted sample = 
= 
(where ∝ was use in place of μ in the expressed fraction)
= 0.003 mg/μL
The dilution of the sample is from 10-to-1 indicating that the original concentration is ten times higher; as such the protein concentration of the original solution can be calculated as:
protein concentration of the original solution = 10 × concentration of the diluted sample.
= 10 × 0.003 mg/μL
= 0.03 mg/μL
= 0.03g/mL
Hence, the protein concentration of the original solution is known to be 0.03g/mL
Determine the mass of each of the following amounts. a. 1.366 mol of
NH3
, b. 0.120 mol of glucose,
C6H12O6
, c. 6.94 mol barium chloride,
BaCl2
, d. 0.005 mol of propane,
C3H8
