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2 years ago

I really need help with this

Mathematics

1 answer:

Andreyy892 years ago

3 0

Answer:

x = 67

Step-by-step explanation:

If the measure of the entire chord is 166°, then if you add the two angles that form it together, it will equal 166.

So,

x + 15 + x + 17 = 166

Simplify.

2x + 32 = 166

Subtract 32 from both sides.

2x = 134

Divide both sides by 2.

x = 67

I hope this helps! Feel free to ask any questions!

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6-2(x+6)=3x+4 ...............................

juin [17]

Answer:

x=−2

Step-by-step explanation:

1 Expand.

6-2x-12=3x+4

6−2x−12=3x+4

2 Simplify 6-2x-126−2x−12 to -2x-6−2x−6.

-2x-6=3x+4

−2x−6=3x+4

3 Add 2x2x to both sides.

-6=3x+4+2x

−6=3x+4+2x

4 Simplify 3x+4+2x3x+4+2x to 5x+45x+4.

-6=5x+4

−6=5x+4

5 Subtract 44 from both sides.

-6-4=5x

−6−4=5x

6 Simplify -6-4−6−4 to -10−10.

-10=5x

−10=5x

7 Divide both sides by 55.

-\frac{10}{5}=x

−

8 Simplify \frac{10}{5}

to 22.

-2=x

−2=x

9 Switch sides.

x=-2

x=−2

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2 years ago

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Solve 2cos ²y -siny -1=0 for 0° ≤y≤360°

natima [27]

$\displaystyle\bf\\2cos^2y -sin\,y -1=0~~~for~~0^o\leq y \leq360^o\\\\cos^2y=1-sin^2y\\\\2(1-sin^2y) -sin\,y -1=0\\\\2-2sin^2y-sin\,y-1=0\\\\-2sin^2y-sin\,y+2-1=0\\\\-2sin^2y-sin\,y+1=0~~~\Big|\times(-1)\\\\2sin^2y+sin\,y-1=0$

$\displaystyle\bf\\\boxed{\bf sin\,y=x}\\\\2x^2+x-1=0\\\\x_{12}=\frac{-b\pm\sqrt{b^2-4ac}}{2a}=\frac{-1\pm\sqrt{1-4\cdot2\cdot(-1)}}{2\cdot2}=\\\\=\frac{-1\pm\sqrt{1+8}}{4}=\frac{-1\pm\sqrt{9}}{4}=\frac{-1\pm3}{4}\\\\x_1=\frac{-1+3}{4}=\frac{2}{4}=\boxed{\bf\frac{1}{2}}\\\\x_2=\frac{-1-3}{4}=\frac{-4}{4}=\boxed{\bf-1}\\\\sin\,y=\frac{1}{2}\\\\\boxed{\bf y_1=\frac{\pi}{6}~~or~~(30^o)}\\\\\boxed{\bf y_2=\frac{5\pi}{6}~~or~~(150^o)}\\\\sin\,y=-1\\\\\boxed{\bf y_3=\frac{3\pi}{2}~~or~~(270^o)}$