A) А 3.6 cm 3.2 cm B В С 4.5 cm

Hilda's personal information is shown below. According to the following table what is her hypothetical

o-na [289]

Answer:

606

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

a moving sidewalk at an airport moves at a rate of 1.2 ft / SEC. Walking on the moving sidewalk, a person travels 106 ft Ford an

Digiron [165]

A moving sidewalk at an airport moves at a rate of 1.7 ft/sec. Walking on the moving sidewalk, a person travels 104 ft forward in the time it takes to travel 52 ft in the opposite direction.

8 0

3 years ago

How far did Eddie travel after his break? (The break is the part with only the straight line!)

densk [106]

The break ended at 4pm when he was at 15 km.

The ride ended at 6pm when he was at 45 km.

From 4 to 6pm he rode 45 - 15 = 30 km.

7 0

4 years ago

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How do you solve for a and b showing your work

Mariulka [41]

Answer:

a) 4

b) $\frac{1}{2} \sqrt{y^5}$

Step-by-step explanation:

PART A

Simplify the expression by solving out the square roots.

$\frac{\sqrt{16} \sqrt{p} }{\sqrt{p}}$ = $\frac{4 \sqrt{p} }{\sqrt{p}}$

You can cancel out the $\sqrt{p}$ on the top and bottom.

So, a should be 4.

PART B

Solve out the square root. The square root is pretty much the 1/2 power, so you can divide the exponents by half.

$\frac{\sqrt{y^{10}} }{\sqrt{4y^{5}} }$ = $\frac{y^{5}}{2y^{\frac{5}{2}} }$

You can subtract exponents to divide them. So the y variable becomes $y^{5 - 5/2}$ , or $y^{5/2}$ .

Then, the overall expression is $\frac{1}{2} y^{\frac{5}{2} }$ , or you can turn that into $\frac{1}{2} \sqrt{y^5}$ .

5 0

4 years ago

Rachel has a collection of 40 stuffed animals. 3/8 of the animals are bears and are dogs. How many bears and dogs does she have?

Ludmilka [50]

Answer:

total animal 40

number of bears are 40×3/8=15

number of dogs will be 40 - 15 = 35

Step-by-step explanation:

hope it helped u buddy

5 0

4 years ago

A)А3.6 cm3.2 cmB ВС4.5 cm​

A)А3.6 cm3.2 cmB ВС4.5 cm