All categories

3 years ago

What is the radius of a circle with a diameter of 6 meters

Mathematics

2 answers:

Tpy6a [65]3 years ago

8 0

3 meters
radius = d/2

Hope this helps ;)

FromTheMoon [43]3 years ago

7 0

Answer:

the radius is 3 m

Step-by-step explanation:

the radius of a circle is always one half of the diameter.

Here the diameter is 6 m, so the radius is 3 m.

You might be interested in

A pair of jeans are originally $39.50 and are 15% off. The sales tax is 7%. After the discount and tax, how much will the total

Romashka [77]

Answer:

$35.93

Step-by-step explanation:

15% of 39.50= 33.58

7% of 33.58= 35.93

3 0

3 years ago

When do you use trig functions?

Zielflug [23.3K]

When you have all three sides

7 0

3 years ago

At 10:05 a.m., there are 2 microscopic bacteria cells in the bottle. At 10:15 a.m., there are 8 cells in the bottle.

zloy xaker [14]

Answer: At 10:20 a.m., there will be 16 cells in the bottle.

At 10:30 a.m. there will be 64 cells in the bottle .

Step-by-step explanation:

Since we have given that

At 10:05 a.m. number of microscopic bacteria cells in the bottle = 2

At 10:15 a.m. number of microscopic bacteria cells in the bottle = 8

It means in every 5 times the number of microscopic bacteria cells in the bacteria gets twice itself.

So, by following the same pattern we can get that,

At 10:20 a.m. number of microscopic bacteria cells in the bottle is given by

$8\times 2=16$

Hence, At 10:20 a.m., there will be 16 cells in the bottle.

Similarly,

At 10:25 a.m. number of microscopic bacteria cells in the bottle is given by

$16\times 2=32$

At 10:30 a.m. number of microscopic bacteria cells in the bottle will be

$32\times 2=64$

Hence, At 10:30 a.m. there will be 64 cells in the bottle .

8 0

3 years ago

Read 2 more answers

22 points. The windows on the top row of a building are similar to the windows on the bottom row. Rectangle ABCD is similar to r

juin [17]

PQ are the first two letters and AB are the first two letters.

Since the windows are similar the letters in one are in the same orientation as the other ones.

This means PQ would be the same as AB

PQ = 60

The answer is A. 60 in.

5 0

3 years ago

Read 2 more answers

In a start-up company which has 20 computers, some of the computers are infected with virus. The probability that a computer is

Alex777 [14]

Answer:

(1) The probability that the technician tests at least 5 computers before the 1st defective computer is 0.078.

(2) The probability at least 5 computers are infected is 0.949.

Step-by-step explanation:

The probability that a computer is defective is, p = 0.40.

(1)

Let X = number of computers to be tested before the 1st defect is found.

Then the random variable $X\sim Geo(p)$ .

The probability function of a Geometric distribution for k failures before the 1st success is:

$P (X = k)=(1-p)^{k}p;\ k=0, 1, 2, 3,...$

Compute the probability that the technician tests at least 5 computers before the 1st defective computer is found as follows:

P (X ≥ 5) = 1 - P (X < 5)

= 1 - [P (X = 0) + P (X = 1) + P (X = 2) + P (X = 3) + P (X = 4)]

$=1 -[(1-0.40)^{0}0.40+(1-0.40)^{1}0.40+(1-0.40)^{2}0.40\\+(1-0.40)^{3}0.40+(1-0.40)^{4}0.40]\\=1-[0.40+0.24+0.144+0.0864+0.05184]\\=0.07776\\\approx0.078$

Thus, the probability that the technician tests at least 5 computers before the 1st defective computer is 0.078.

(2)

Let Y = number of computers infected.

The number of computers in the company is, n = 20.

Then the random variable $Y\sim Bin(20,0.40)$ .

The probability function of a binomial distribution is:

$P(Y=y)={n\choose y}p^{y}(1-p)^{n-y};\ y=0,1,2,...$

Compute the probability at least 5 computers are infected as follows:

P (Y ≥ 5) = 1 - P (Y < 5)

= 1 - [P (Y = 0) + P (Y = 1) + P (Y = 2) + P (Y = 3) + P (Y = 4)] $=1-[{20\choose 0}(0.40)^{0}(1-0.40)^{20-0}+{20\choose 1}(0.40)^{1}(1-0.40)^{20-1}\\+{20\choose 2}(0.40)^{2}(1-0.40)^{20-2}+{20\choose 3}(0.40)^{3}(1-0.40)^{20-3}\\+{20\choose 4}(0.40)^{4}(1-0.40)^{20-4}]\\=1-[0.00004+0.00049+0.00309+0.01235+0.03499]\\=1-0.05096\\=0.94904$

Thus, the probability at least 5 computers are infected is 0.949.

7 0

3 years ago