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2 years ago

Find the value of X.

Mathematics

2 answers:

Olegator [25]2 years ago

6 0

Answer:

answer: c

Step-by-step explanation:

C is the answer because 35 × 2 = 70 and sense this is a complementary angle it will add up to 90 degrees and 70 + 20 = 90 Hope that helps/explains well!

elena55 [62]2 years ago

3 0

Answer is c because it is a right angle so 90-20=70. Then 70 divided by 2= 35

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3 years ago

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2 years ago

Read 2 more answers

A steel pipe is being carried down a hallway 9 ft wide. At the end of the hall there is a right-angled turn into a narrower hall

Rudiy27

Answer:

21.62m

Step-by-step explanation:

first draw the the pipe

second you need know wich is the angle between the pipe and the corner

β=Tan^-1(6/9)=33.7

find the components using tow triangles

a=9/cos(33.7)=10.81m

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finally sum the leghts

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attached procedure

8 0

2 years ago

Verify that this trigonometric equation is an identity?

Vlada [557]

$\cot x\sec^4 x=\cot x+2\tan x+\tan^3x\\\\L=\dfrac{\cos x}{\sin x}\cdot\dfrac{1}{\cos^4x}=\dfrac{1}{\sin x}\cdot\dfrac{1}{\cos^3x}=\dfrac{1}{\sin x\cos^3x}\\\\R=\dfrac{\cos x}{\sin x}+2\cdot\dfrac{\sin x}{\cos x}+\dfrac{\sin^3x}{\cos^3x}\\\\=\dfrac{\cos x\cos^3x}{\sin x\cos^3x}+\dfrac{2\sin x\cos^2x}{\cos x\sin x\cos^2x}+\dfrac{\sin^3x\sin x}{\cos^3x\sin x}\\\\=\dfrac{\cos^4x+2\sin^2x\cos^2x+\sin^4x}{\sin x\cos^3x}\\\\=\dfrac{(\cos^2x)^2+2\sin^2x\cos^2x+(\sin^2x)^2}{\sin x\cos^3x}$

$=\dfrac{(\cos^2x+\sin^2x)^2}{\sin x\cos^3x}=\dfrac{1}{\sin x\cos^3x}=L\\\\Used:\\\tan(a)=\dfrac{\sin(a)}{\cos(a)}\\\cot(a)=\dfrac{\cos(a)}{\sin(a)}\\\sec(a)=\dfrac{1}{\cos(a)}\\\sin^2a+\cos^2a=1\\(a+b)^2=a^2+2ab+b^2$

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3 years ago