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lions [1.4K]
3 years ago
10

In Coachella, California the temperature was 9 degrees below zero at 2 am. By 5 am the temperature had dropped by an additional

7 degrees. By 1 pm the next day the temperature had risen by 12 degrees. What was the temperature at 5 am
Mathematics
1 answer:
kvasek [131]3 years ago
3 0

Answer:

The temperature at 5 am is 16 degrees below zero.

Step-by-step explanation:

The temperature at 2 am is 9 degrees below zero:

T_{2_{am}} = -9

Since at 5 am the temperature had dropped by an additional 7 degrees, we have:        

T_{5_{am}} = T_{2_{am}} - 7      

T_{5_{am}} = -9 - 7 = -16

Therefore, the temperature at 5 am is 16 degrees below zero.

I hope it helps you!      

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gtnhenbr [62]
The answer is 488 sq cm.

rectangle:

A=lw
A=(22)(17)
A=374

triangle:
A=(1/2)bh
A=(1/2)(19)(22-10)
A=(1/2)(19)(12)
A=(1/2)228
A=114

rectangle + triangle:
374 + 114 = 488
5 0
3 years ago
If m∠EBF = 6x + 4 and m∠CBF = 7x – 2, find m∠EBF.
olganol [36]

Answer:

78

Step-by-step

I hope it's helped

6 0
3 years ago
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10. Your Turn: Find the equation of a line that is perpendicular to y=2x+7, and passes through the point (-4, 7). SHOW YOUR WORK
agasfer [191]
Alright, so since the slope of the perpendicular line is -1/(slope), we get (-1/2)=-1/2 and y=(-1/2)x + something. Plugging 7 in as y and -4 in as x, we get 7=(-1/2)(4)+something (let's make it a variable b), and multiplying it out we get 7=-2+b. Adding 2 to both sides, we get 7+2=9=b, so the perpendicular line equation is therefore y=(-1/2)x+b<span />
6 0
3 years ago
20 POINTS!!! Use the quadratic formula above to solve for h(t) = -4.9t^2 + 8t + 1 where h is the height of the ball in meters an
Elina [12.6K]

Answer:

Two solutions: -0.12 and 1.75.

Step-by-step explanation:

The quadratic formula is:

\begin{array}{*{20}c} {\frac{{ - b \pm \sqrt {b^2 - 4ac} }}{{2a}}} \end{array}. Assuming that the x² term is a, the x term is b, and the constant is c, we can plug the values into the equation.

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {8^2 - 4\cdot-4.9\cdot1} }}{{2\cdot-4.9}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {64 + 19.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {83.6} }}{{-9.8}}} \end{array}

\begin{array}{*{20}c}{\frac{{ - 8 \pm \sqrt {9.14} }}{{-9.8}}} \end{array}

\frac{-8 + 9.14}{-9.8} = -0.12

\frac{-8-9.14}{-9.8} =1.75

Hope this helped!

3 0
3 years ago
What is 4/5 plus 2/3
omeli [17]

Answer:

1 \frac{7}{15}  or

\frac{22}{15}

Step-by-step explanation:

6 0
3 years ago
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