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Marianna [84]
3 years ago
11

How do you solve special right triangles with 45-45-90

Mathematics
1 answer:
expeople1 [14]3 years ago
3 0
By doing by over 2 it will equal yeah
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Given: AABC-ADEF
Jlenok [28]
The answer is B because those triangles are congruent
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3 years ago
Ryan and Danielle competed in a bike race.Ryan biked 11,988 meters and Danielle 13,336 meters.How much more did Danielle bike th
salantis [7]

Answer:

1348 more meters.

Step-by-step explanation:

Subtract

13336 - 11988 = 1348

Danielle biked 1348 more meters than Ryan

If my answer is incorrect, pls correct me!

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3 years ago
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a 4

b 3

c 9

d 4

Step-by-step explanation:

id.k

7 0
3 years ago
P^2+2p-63=0<br> solve by completing the square
algol [13]

Step-by-step explanation:

p^2+2p=63

p^2+2p+1^2=63+1^2

p^2+2p+1=64

(p+1)^2=64

p+1=8

p=8-1

p=7

7 0
3 years ago
Frank, who lives in Texas, and his sister Lilly, who lives in Japan, correspond regularly. From what he can tell from the postma
Hoochie [10]

Question:

The available options are:

(A) There is convincing evidence that there is no difference in the mean delivery times.

(B) There is convincing evidence that there is a difference in the mean delivery times.

(C) There is convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan.

(D) There is not convincing evidence that the mean delivery time from Japan to Texas is greater than the mean delivery time from Texas to Japan. (E) The t-test cannot be used for sample sizes that are this small.

Answer:

The correct option is;

(A) There is convincing evidence that there is no difference in the mean delivery times.

Step-by-step explanation:

Here we have the formula for the two-sample t-test given s;

t =\frac{\overbar\overline{\rm x}_1 - \overbar\overline{\rm x}_2 }{\sqrt{\frac{\sigma ^2_1}{n_1} } +\frac{\sigma ^2_2}{n_2} }}    

To Texas N₁ = 12,  \overline{\rm x}_1 =8.74 σ₁ = 2.92 SE Mean₁ = 0.84

To Japan N₂ = 9  \overline{\rm x}_2 = 6.75 σ₂ = 2.56 SE Mean₁ = 0.85

t =   1.667

Where the null hypothesis is

mu To Texas = mu To Japan and the alternative is

mu To Texas > mu To Japan

Here since the observed P value of P = 0.058 is greater than the significance level of 0.05 we fail to reject the null hypothesis and we will therefore, not accept the alternative hypothesis.

Hence, there is convincing evidence that there is no difference in the mean delivery times.  

3 0
3 years ago
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