Answer:
13.89% of students are willing to report cheating by other students.
Step-by-step explanation:
We are given the following in the question:
Sample size, n = 180
Number of students who reported cheating, x = 25
We have to find the proportion of the students are willing to report cheating by other students.
Proportion of students can be calculate as
Thus, 13.89% of students are willing to report cheating by other students.
Answer:
4√10
Step-by-step explanation:
Hello!
Let's first simplify the radical.
We can do this by expanding the radical:
We need to pull out a perfect square factor to expand a radical and simplify it. In 45, we have 9 and 5 multiplied, and 9 is a perfect square.
Let's work with √45:
- √45 can be written as √9 * √5 (using the rule √ab = √a * √b)
- √9 simplifies to 3, so it is 3√5
Now we can simplify the operation in the parenthesis by combining like terms:
- 3√5 + √5
- √5 + √5 + √5 + √5
- 4√5
Now using the same rule as above, we can multiply the values:
Your solution is 4√10
Answer:
79
Step-by-step explanation:
60<xy<100
y -2 =x
if it is prime
y cannot be even
so y could be 1,3,5,7,9
x would then be 9,1,3,5,7
but to be between 60 and 100
x must be 7 or 9
so the number must be 79 or 57
57 is not prime so
the number is 79
Answer:
there is a 3/4 chance that they pass will be completed, 3/4=75%.
Step-by-step explanation:
Thats all I got, I hope this may help tho! :)
Answer:
Its 6.5
Step-by-step explanation:
