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san4es73 [151]
3 years ago
12

��2222 is the diameter of a circle. The coordinates are �(−2, −3) and �(−12, −5). At what coordinate is the center of the circle

located? A. (5, 1) B. (−5, −1) C. (−4, −7) D. (−7, −4)
Mathematics
1 answer:
miv72 [106K]3 years ago
7 0

Answer:

D ). (-7,-4)

Step-by-step explanation:

To locate the position or the location of the centre of the circle we have to bear in mind that the center of the circle is the midpoint of the diameter line.

Formula for midpoint of a line is given below

Midpoint= (X1+x2)/2 ,(y1+y2)/2

Where X1= -2,y1= -3

X2= -12, y2= -5

The midpoint= (-2+(-12))/2,(-3+(-5))/2

Midpoint= (-2-12)/2,(-3-5)/2

Midpoint= (-14)/2,(-8)/2

Midpoint=( -7,-4)

The center of the circle is located at the point (-7,-4)

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Students are designing a new town as part of a social studies project on urban planning. ey want to place the town’s high school
-Dominant- [34]

Answer:

  c, d.  see attached

  e. about 2.96 miles; about $1.63 million

Step-by-step explanation:

e. The x-coordinates of points A and B are 1/3 and 2/3 of the x-coordinate of "Downtown", respectively. The y-coordinates of A and B are 2/3 and 1/3 of the y-coordinate of "Town pool", respectively. Then the distances from A and B to the Mall can be found using the Pythagorean theorem:

  A to Mall = √(4² +(10/3)²) = √(244/9) ≈ 5.20683 . . . miles

  B to Mall = √(8² +(5/3)²) = √(601/9) ≈ 8.17177 . . . miles

The difference in distance is ...

  (BM -AM) = 8.17177 -5.20683 = 2.96493 . . . miles

The mall is about 2.96 miles farther from point B than from point A.

The additional cost is the difference in miles multiplied by the cost per mile:

  (2.96 mi)($0.550 M/mi) = $1.63 M

The additional cost of the longer road is about $1.63 million.

5 0
3 years ago
At the farmers market each of the 94 vendors makes $502 in profit each weekend.How much profit will all vendors make on saturday
bixtya [17]
The answer is 430.28
7 0
3 years ago
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Question 71
yuradex [85]

Answer:

given

p=q^3

p=40

______

q=(p)^1/3

q=(40)^1/3-->q=2(5)^1/3

Now

the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.

finally the value of p gonna be

p=q^3

p=(5^1/3) ^ 3

p=5

3 0
3 years ago
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Find the area of this triangle, round to the nearest tenth, I will give brainliest
Setler79 [48]

Answer:

59.15 in^2

Step-by-step explanation:

Using Heron's formula

semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4

Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2

4 0
2 years ago
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What is the value of x?
Phantasy [73]

Answer:

value of x = 5.8 mm

Step-by-step explanation:

We have given,

Two right triangles EDH and EDG.

In right triangle EDH, EH = 56mm , DH = 35 mm

Using Pythagoras theorem we can find ED.

i.e EH² = ED²+DH²

56²=ED²+35²

ED²=56²-35²

ED = √(56²-35²) = 7√39 = 43.71 mm

Now, Consider right triangle EDG

Here, EG=44.8mm , GD = x+4  and ED = 7√39

Again using Pythagoras theorem,

EG² = ED² + DG²

44.8²= (7√39)²+ (x+4)²

(x+4)² = 44.8² - (7√39)²

x+4 = √(44.8² - (7√39)²)

x+4 = 9.8

or x = 9.8 - 4 = 5.8 mm

Hence we got the value of x = 5.8 mm

6 0
4 years ago
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