Answer:
c, d. see attached
e. about 2.96 miles; about $1.63 million
Step-by-step explanation:
e. The x-coordinates of points A and B are 1/3 and 2/3 of the x-coordinate of "Downtown", respectively. The y-coordinates of A and B are 2/3 and 1/3 of the y-coordinate of "Town pool", respectively. Then the distances from A and B to the Mall can be found using the Pythagorean theorem:
A to Mall = √(4² +(10/3)²) = √(244/9) ≈ 5.20683 . . . miles
B to Mall = √(8² +(5/3)²) = √(601/9) ≈ 8.17177 . . . miles
The difference in distance is ...
(BM -AM) = 8.17177 -5.20683 = 2.96493 . . . miles
The mall is about 2.96 miles farther from point B than from point A.
The additional cost is the difference in miles multiplied by the cost per mile:
(2.96 mi)($0.550 M/mi) = $1.63 M
The additional cost of the longer road is about $1.63 million.
Answer:
given
p=q^3
p=40
______
q=(p)^1/3
q=(40)^1/3-->q=2(5)^1/3
Now
the value of half of q , (2(5)^1/3)÷(2) ,is 5^1/3.
finally the value of p gonna be
p=q^3
p=(5^1/3) ^ 3
p=5
Answer:
59.15 in^2
Step-by-step explanation:
Using Heron's formula
semiperimeter , s = 1/2 ( 28.8+18+12) = 29.4
Area = sqrt ( 29.4(29.4-28.8)(29.4-18)(29.4-12) ) = 59.15 in^2
Answer:
value of x = 5.8 mm
Step-by-step explanation:
We have given,
Two right triangles EDH and EDG.
In right triangle EDH, EH = 56mm , DH = 35 mm
Using Pythagoras theorem we can find ED.
i.e EH² = ED²+DH²
56²=ED²+35²
ED²=56²-35²
ED = √(56²-35²) = 7√39 = 43.71 mm
Now, Consider right triangle EDG
Here, EG=44.8mm , GD = x+4 and ED = 7√39
Again using Pythagoras theorem,
EG² = ED² + DG²
44.8²= (7√39)²+ (x+4)²
(x+4)² = 44.8² - (7√39)²
x+4 = √(44.8² - (7√39)²)
x+4 = 9.8
or x = 9.8 - 4 = 5.8 mm
Hence we got the value of x = 5.8 mm