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Klio2033 [76]
3 years ago
10

Use the normal distribution and the given sample results to complete the test of the given hypotheses. Assume the results come f

rom a random sample and use a 5% significance level.
Test H0: p = 0.25 vs Ha: p < 0.25 using the sample results p(hat) = 0.15 with n = 102
Round your answer for the test statistic to two decimal places, and your answer for the p-value to three decimal places.
Mathematics
1 answer:
sveta [45]3 years ago
7 0

Answer:

Test statistic = - 2.33

Pvalue = 0.010 (3 decimal places)

Step-by-step explanation:

Given :

H0: p = 0.25 vs Ha: p < 0.25

Phat = 0.15

Sample size, n = 102

α = 0.05

The test statistic :

(Phat - p) / (√p(1 - p) /n)

1 - p = 1 - 0.25 = 0.75

(0.15 - 0.25) / (√0.25(0.75) /102)

-0.1 / √0.0018382

-0.1 / 0.0428742

Test statistic = - 2.33

The Pvalue using the test statistic score obtained :

P(Z < - 2.33) = 0.0099031 = 0.010

Pvalue < α ; Reject H0

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a- 32,52

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Step-by-step explanation:

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Donna is going to swim 29 laps. She has completed 16 laps. What fraction of laps has she completed? What fraction of her swim re
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Answer:

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3 years ago
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lys-0071 [83]

Answer:

(x+1)^2 + (y- 3.5)^2 =64

Step-by-step explanation:

We are given that  endpoints of a diameter at the points (7,2) and (-9,5).

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So, first find the mid point of diameter

Formula : x=\frac{x_1+x_2}{2} , y=\frac{y_1+y_2}{2}

(x_1,y_1)=(7,2)\\(y_1,y_2)=(-9,5)

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Standard form of the equation of the circle : (x -h)^2 + (y- k)^2 = r^2

(h,k )=(-1,3.5)

r=\frac{\sqrt{256}}{2}

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =(\frac{\sqrt{256}}{2})^2

Equation of the circle : (x+1)^2 + (y- 3.5)^2 =64

Hence  the standard form of the equation of the circle with endpoints of a diameter at the points (7,2) and (-9,5) is  (x+1)^2 + (y- 3.5)^2 =64

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Answer:

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Step-by-step explanation:

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