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2 years ago

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Mathematics

1 answer:

masya89 [10]2 years ago

7 0

Answer:

See below

Step-by-step explanation:

x(x-2y)-(y-x)2

Final result :

-y2

Step by step solution :

Step 1 :

Equation at the end of step 1 :

x • (x - 2y) - (y - x)2

Step 2 :

2.1 Evaluate : (y-x)2 = y2-2xy+x2

Final result :

-y2

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Help me If x=1/2 and y=2/3 , find the value of xy+ (x+ y)

Dima020 [189]

Answer:

3/2

Step-by-step explanation:

7 0

2 years ago

Solve the equation. 3(k−6)=15

Natali [406]

Answer:

K = 11

Step-by-step explanation:

3(k - 6) = 15

3k - 18 = 15

3k = 15 + 18

3k = 33

K = 33/3

K = 11

Thus, the value of K is 11

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2 years ago

Which expressions are equivalent to when x0? Check all that apply.

Genrish500 [490]

We have that

$\frac{(x+4)}{3} / \frac{6}{x} = \frac{x*(x+4)}{3*6} \\ \\ = \frac{( x^{2} +4x)}{18}$

therefore

case a)
$\frac{(x+4)}{3} * \frac{x}{6}$
Is equivalent

case b)
$\frac{6}{x} * \frac{(x+4)}{3}$
Is not equivalent

case c)
$\frac{x}{6} * \frac{(x+4)}{3}$
Is equivalent

case d)
$\frac{(2 x^{2} +4x)}{6}$
Is not equivalent

case e)
$\frac{(2 x^{2} +4x)}{18}$
Is equivalent

Hence

the answer is

$\frac{(x+4)}{3} * \frac{x}{6}$

$\frac{x}{6} * \frac{(x+4)}{3}$

$\frac{(2 x^{2} +4x)}{18}$

3 0

2 years ago

Read 2 more answers

Is the expression 2f + 4f + 2 – 3 equivalent to 6f – 1? 6f – 1 evaluated at f = 9 is 53. 2f + 4f + 2 – 3 evaluated at f = 9 is a

morpeh [17]

We have that

the expression 2f + 4f + 2 – 3-------> we can group it (2f+4f)+(2-3)
(2f+4f)+(2-3)=(6f-1)
therefore
the expression [2f + 4f + 2 – 3] is equivalent to [6f-1]

if the expression [6f-1] for f=3 is 17
then
the expression [2f + 4f + 2 – 3] for f=3 is also 17

let's check it
[2*3 + 4*3 + 2 – 3]--------> [6+12+2-3]=[20-3]=17------> is ok

6 0

3 years ago

Read 2 more answers

I neeeeeeeeeeeeeed help

masya89 [10]

9514 1404 393

Answer:

14 +2i

Step-by-step explanation:

For this sort of problem, you can treat i as though it were a variable. Combine like terms.

(8 -7i) +(6 +9i) = (8 +6) +(-7 +9)i

= 14 +2i

7 0

3 years ago