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ICE Princess25 [194]
3 years ago
5

William receives a weekly allowance according to the following formula: For each day that he remembers to do his chores, he eams

51.50, and for each day that he doesn't remember to do his chores, he loses
50.25. What amount of allowance would William receive for a week in which he remembers to do his chores on five days and forgets to do them on two days?
Mathematics
1 answer:
mash [69]3 years ago
5 0
Answer = 150.75

50.25 * 5 = 251.25
50.25 * 2= 100.5
251.25-100.5= 150.75
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What's the "Build Time" and "Paint/Assembly Time"
erik [133]

5x + 2y=50

or

5x + 2y<=50 (less than or equal to)

then

x + 2y=30

or

x + 2y<=30(less than or equal to)

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Which equation can be used to find 30 percent of 600
agasfer [191]
A/b *100
For example,
30/600.
30/600=0.05
0.05*100=5%
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3.<br> B<br> ge<br> 18cm<br> A<br> 60°<br> 20cm<br> с<br> Calculate the size of angle ABC.
uysha [10]

Answer:

Step-by-step explanation:

8 0
3 years ago
9. A store is offering a 20% discount on all sales over $50. If you purchase a shirt and a pair of jeans for $62.50, what
Serga [27]

Answer:

B. 12.50.

Step-by-step explanation:

62.50 x .20 = 12.5

Hope this helps and good luck.

3 0
3 years ago
Read 2 more answers
the figure below shows a circle centre of radius 10 cm the chord PQ=16cm calculate the area of the shaded region​
m_a_m_a [10]

Step-by-step explanation:

OPQ originally forms a sector, the formula for sector is

\frac{x}{360} \pi {r}^{2}

where x is the degrees of rotation between the two radii.

We know three sides length and is trying to find an angle between the radii so we can use law of cosines which states that

16 =  \sqrt{10 {}^{2} + 10 {}^{2}   - 2(100) \times  \cos(o) }

This isn't the standard formula, it's for this problem

16 =  \sqrt{200 - 200 \times  \cos(o) }

16 =  \sqrt{200  - 200 \cos(o) }

256 = 200 - 200 \cos(o)

56 =  - 200 \cos(o)

-  \frac{7}{25}  =  \cos(o)

\cos {}^{ - 1} (  - \frac{7}{25} )  =  \cos {}^{ - 1} ( \cos(o) )

106.26 = o

So we found our angle of rotation, which is 106.26

Now, we do the sector formula.

\frac{106.26}{360} (100)\pi

\frac{10626}{360} \pi

is the area of sector.

Now let find the area of triangle, we can use Heron formula,

The area of a triangle is

\sqrt{s(s - a)(s - b)(s - c)}

where s is the semi-perimeter.

To find s, add all the side lengths up, 10,10,16 and divide it by 2.

Which is

\frac{36}{2}  = 18

\sqrt{18(18 - 10)(18 - 10)(18 - 16)}

\sqrt{18(8)(8)(2)}

\sqrt{(36)(64)}

6  \times 8 = 48

So our area of the triangle is 48. Now, to find the shaded area subtract the main area,( the sector of the circle) by the area of the triangle so we get

\frac{10626}{360}  - 48

Which is an approximate or

44.73

6 0
2 years ago
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