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gladu [14]
3 years ago
15

A car needs fixing and Abe can fix it for $70 per hour with a $130 part, but Gabe can fix it for $80 an hour with a $40 part.How

long will it take for both Abe and Gabe to cost the same amount?
Mathematics
1 answer:
patriot [66]3 years ago
7 0

Answer:

9 hours

Step-by-step explanation:

Abe's charge  =   Gabe's charge

$130+($70/hr)h = $40+($80/hr)h

Then 130 + 70h = 40 + 80h, or

           90           =   10h, or h = 90/10 = 9

When 9 hours have passed, the amount charged by each person will be temporarily equal.

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