Question

Asha makes a conjecture that the perimeter of a square whose sides are an odd integer is always even. Which choice is the best proof of her conjecture?

Answer 1

Answer: bottom left one just trust me

Step-by-step explanation:

Answer 2

Answer: Bottom left corner

Let n be an odd number. Because 4n is a multiple of 2, it is an even number.

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Explanation:

The square has a side length of n, so its perimeter is 4n since n+n+n+n = 4n.

We can rewrite 4n as 2*2n = 2m where m = 2n is an integer. Any number in the form 2*(some integer) is always even. Even numbers always have 2 as a factor.

So whenever it comes to proving something is even, the ultimate goal is to get it into the form 2*(some integer). If we can do this, then the number is even. If not, then the number is odd.