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zhannawk [14.2K]
3 years ago
10

Asha makes a conjecture that the perimeter of a square whose sides are an odd integer is always even. Which choice is the best p

roof of her conjecture?

Mathematics
2 answers:
raketka [301]3 years ago
7 0

Answer: bottom left one just trust me

Step-by-step explanation:

Ivan3 years ago
4 0

Answer: Bottom left corner

Let n be an odd number. Because 4n is a multiple of 2, it is an even number.

============================================

Explanation:

The square has a side length of n, so its perimeter is 4n since n+n+n+n = 4n.

We can rewrite 4n as 2*2n = 2m where m = 2n is an integer. Any number in the form 2*(some integer) is always even. Even numbers always have 2 as a factor.

So whenever it comes to proving something is even, the ultimate goal is to get it into the form 2*(some integer). If we can do this, then the number is even. If not, then the number is odd.

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Step-by-step explanation:

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3). 5 is a possible solution due to the sum of 5 and 6 being larger than 10

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Hope this helped! (:

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