This answer did not come from me but credit to ApusApus
We have been given that adult male heights are normally distributed with a mean of 70 inches and a standard deviation of 3 inches. The average basketball player is 79 inches tall.
We need to find the area of normal curve above the raw score 79.
First of all let us find the z-score corresponding to our given raw score.
, where,
,
,
,
.
Upon substituting our given values in z-score formula we will get,
Now we will find the P(z>3) using formula:
Using normal distribution table we will get,
Let us convert our answer into percentage by multiplying 0.00135 by 100.
Therefore, approximately 0.135% of the adult male population is taller than the average basketball player and option A is the correct choice.
Answer:
![2x^{2}y](https://tex.z-dn.net/?f=2x%5E%7B2%7Dy)
Step-by-step explanation:
I don’t think it’s any of them i went through and tried all of them and none of them were equal. I honestly could just suck
Answer:
![x=7.5](https://tex.z-dn.net/?f=x%3D7.5)
Step-by-step explanation:
![x+4.5=\frac{36}{3}=12](https://tex.z-dn.net/?f=x%2B4.5%3D%5Cfrac%7B36%7D%7B3%7D%3D12)
![x=12-4.5=7.5](https://tex.z-dn.net/?f=x%3D12-4.5%3D7.5)