3 years ago

Find the arc length

Mathematics

1 answer:

umka21 [38]3 years ago

7 0

Answer:

39/2 π ft^2

Step-by-step explanation:

2(13)(270)/360

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Suppose the scores on a test given to all juniors in a school district are normally distributed with a mean of 74 and a standard

ivann1987 [24]

Answer:

$\mu -\sigma = 66 , \mu +\sigma = 82$

$\mu -2\sigma = 58 , \mu +2\sigma = 90$

$\mu -3\sigma = 50 , \mu +3\sigma = 98$

And in the figure attached we see the limits with the percentages associated.

Step-by-step explanation:

For this case we know that the random variable of interest is the scores on a test given to all juniors in a school district follows a normal distribution with the following parameters:

$X \sim N(\mu= 74, \sigma =8)$

For this case we know from the empirical rule that within one deviation from the mean we have approximately 68.2% of the data, within 2 deviations from the mean we have 95% and within 3 deviation 99.7%

We can find the limits and we got:

$\mu -\sigma = 66 , \mu +\sigma = 82$

$\mu -2\sigma = 58 , \mu +2\sigma = 90$

$\mu -3\sigma = 50 , \mu +3\sigma = 98$

And in the figure attached we see the limits with the percentages associated.