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aev [14]
4 years ago
15

Help! Find x in the given figure. x = inches.

Mathematics
1 answer:
aleksandr82 [10.1K]4 years ago
6 0
There are a few relations related to tangents and secants that you are expected to remember. These problems make use of those.

1. When chords cut each other, the product of the segment lengths of one of them is equal to the product of the segment lengths of the other. Here, one of the chords is a diameter. That is special in that it is the bisector of any chord it crosses at right angles. That means ...
  x·x = 2·6
  x = √12 = 2√3

2. Secants from an external point have the same product of measures to the near and far intersection points with the circle. Since there is only one intersection point with a tangent, the near and far lengths are the same.
  4·(4+8) = x·x
  x = √48 = 4√3
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The ratio of the areas of two similar
dezoksy [38]

Answer: 6 cm

Step-by-step explanation:

Given: The ratio of the areas of two similar  parallelograms is 4:9.

To find : The height of the  bigger one if the smaller is of height 4 cm.

Let h be the height of the  bigger one.

Since the areas of similar figures are proportional to the square of their corresponding sides.

Then, \dfrac{4^2}{h^2}=\dfrac{4}{9}

\dfrac{16}{h^2}=\dfrac{4}{9}\\\\\Rightarrow\ h^2=\dfrac{9}{4}\times16\\\\\Rightarrow\ h^2=36\\\\\Rightarow\ h= 6\ cm\ \ \ \ \text{[ height cannot be negative.]}

Hence, the height of bigger parallelogram = 6 cm

3 0
3 years ago
If you are studying the effects of UV rays on eyesight and you group 10 people together and make them wear sunglasses for 10 wee
Anastasy [175]
The variable of interest would be whether or not their eyes were affected. 
Variables of interest are like independent variables, they are the variable that you are testing for change.
8 0
3 years ago
Read 2 more answers
P(x) = 3x + 4<br> q(X) = 2x^2<br> Find a(p(x))
Kazeer [188]

Answer:

0

Step-by-step explanation:

ap/2

8 0
4 years ago
No files please! thanks
BigorU [14]

Answer:

y = -\frac{1}{3}

2\frac{2}{3}=x

Step-by-step explanation:

To solve a system of equations, solve one or both of the equations for the same variable. Then multiply one of the equations such that the coefficients of one variable are the additive inverse of the variable in the other equation. After doing so, add the two equations, then solve for the other variable using inverse operations. Finally, substitute the value of the other variable into one of the original equations in the system and solve for the unknown variable.

2x + y = 3

y = x - 2

First, manipulate the first equation such that the equation is solved for (y), this can be done using inverse operations,

y = 3 - 2x

y = x - 2

Now multiply the second equation by (2) so that the (x) coefficients are additive inverses of each other,

y = 3 - 2x

2y = 2x - 4

Add the equations,

3y = -1

Inverse operations,

3y = -1

/3     /3

y = -\frac{1}{3}

Now back solve, substitute the value of (y) into the equation and solve for (x),

y=x-3\\

Substitute,

(-\frac{1}{3})=x-3

+3

2\frac{2}{3}=x

5 0
3 years ago
Graph  image 1  for  translation. one unit to the right
rodikova [14]
We use the following reflection rule:
 (x, y) = (x + 1, y)
 We have then:
 M (-3, 1) ---> M '(- 2, 1)
 O (1, 4) ---> O '(2, 4)
 P (3, -1) ----> P '(4, -1)
 Answer:
 The new vertices are
 M '(- 2, 1)
 O '(2, 4)
 P '(4, -1)
 Graph five (last from left to right) is the correct one.
8 0
3 years ago
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