Ask question

Ask question

All categories

3 years ago

14

I. Write the equation of a parabola, in standard form, that goes through these points: (0, 3) (1, 4) (-1, -6) II. Graph the para

bola above. Indicate the vertex and axis of symmetry.

1 answer:

Anna11 [10]3 years ago

7 0

Vertex = (1,4)
Axis of symmetry is x = 1, (1,0) or just 1

<span />

You might be interested in

How many years is 30 months?

Arlecino [84]

2 years and 6 months

hope this helped

mark brainliest :)

3 0

3 years ago

Read 2 more answers

Find the area and the circumference of a circle with diameter 8 cm. Use the value 3.14 for π , and do not round your answers. Be

Illusion [34]

Answer:

Area= 50.24 squared cm.

Circumference= 25.12 cm.

Step-by-step explanation:

To find the area of a circle- A= 3.14*(4 cm squared). ( The 4 cm is your radius. Half of the diameter.) After you square your radius you get 16cm squared. You then go onto multiply the 16 cm squared by 3.14 to get 50.24 cm squared.

To find the circumference of a circle- C= 2*(3.14)*(4cm). (Again the 4cm is your radius. Half of the diameter.) After you multiply the 2 and 3.14 you get 6.28. You then multiply the 6.28 by 4 cm to get 25.12 cm.

7 0

3 years ago

95i is a root of f(x)=x^2 +9025. find the other roots of f(x)

Alex_Xolod [135]

Answer:

Other root is -95i

Step-by-step explanation:

Here, Nature of roots of f(x) is imaginary roots.

Therefore, Roots are conjugate of each other.

Conjugate of x + yi is x - yi.

we get conjugate of 95i as -95i

Verification shows....

(x-95)(x+95i)=0

${x }^{2} - {95}^{2} {i}^{2} = 0 \\ {x }^{2} + {95}^{2} = 0 \\ {x }^{2} + 9025= 0 \\ f(x) = 0$

this, roots are -95i and 95i

5 0

3 years ago

On a coordinate plane, 2 exponential fuctions are shown. Function f (x) decreases from quadrant 2 into quadrant 1 and approaches

Gala2k [10]

Answer:

$g(x)=6(3)^x$

Step-by-step explanation:

We are given that

$f(x)=6(\frac{1}{3})^x$

Function f decreases from quadrant 2 to quadrant 1 and approaches y=0

It cut the y- axis at (0,6) and passing through the point (1,2).

Function g(x) approaches y=0 in quadrant 2 and increases into quadrant 1.

It passing through the point (-1,2) and cut the y-axis at point (0,6).

Reflection across y- axis:

Rule of transformation is given by

$(x,y)\rightarrow (-x,y)$

Using the rule then we get

$g(x)=6(\frac{1}{3})^{-x}=6(3)^x$

By using

$x^{-a}=\frac{1}{x^a}$

Substitute x=-1

$g(-1)=6\times (\frac{1}{3})=2$

Substitute x=0

$g(0)=6$

Therefore, $g(x)=6(3)^x$ is true.

8 0

3 years ago

Read 2 more answers

Evaluate the expression if x=2 and y=1 -4+|y-6|

belka [17]

The answer is one because according to pemdas you must do the parentheses first then do the rest

5 0

3 years ago