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n200080 [17]
3 years ago
11

What happens to the O2 levels during the light and dark?

Chemistry
1 answer:
Lady_Fox [76]3 years ago
5 0

Answer: Hello, This might help. Unidirectional O2 fluxes were measured with 18O2 in a whole plant of wheat cultivated in a controlled environment. At 2 or 21% O2, O2 uptake was maximum at 60 microliters per liter CO2. At lower CO2 concentrations, it was strongly inhibited, as was photosynthetic O2 evolution. At 2% O2, there remained a substantial O2 uptake, even at high CO2 level; the O2 evolution was inhibited at CO2 concentrations under 330 microliters per liter. The O2 uptake increased linearly with light intensity, starting from the level of dark respiration. No saturation was observed at high light intensities. No significant change in the gas-exchange patterns occurred during a long period of the plant life. An adaptation to low light intensities was observed after 3 hours illumination. These results are interpreted in relation to the functioning of the photosynthetic apparatus and point to a regulation by the electron acceptors and a specific action of CO2. The behavior of the O2 uptake and the study of the CO2 compensation point seem to indicate the persistence of mitochondrial respiration during photosynthesis.

Explanation:

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We can also perform a similar calculation for the mass defect and binding energy for nuclear reactions using the masses of the a
sukhopar [10]

Answer:

See Explanation

Explanation:

\frac{235}{92} U + \frac{1}{0} n ---->\frac{137}{52} Te + \frac{97}{40} Zr +2\frac{1}{0} n

Hence the mass defect is;

[235.04393 + 1.00867] - [ 136.92532 + 96.91095 + 2(1.00867)]

=  236.0526 - 235.85361

= 0.19899 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.19899 amu = 0.19899 * 1.66 * 10^-27 = 3.3 * 10^-28 Kg

Binding energy = Δmc^2

Binding energy = 3.3 * 10^-28 Kg * (3 * 10^8)^2 = 2.97 * 10^-11 J

ii) \frac{10}{5}B + \frac{1}{0}n-----> \frac{7}{3} Li + \frac{4}{2} He + Energy

Hence the mass defect is;

[10.01294 + 1.00867] - [7.01600 + 4.00260]

= 11.02161 - 11.0186

= 0.00301 amu

Since 1 amu = 1.66 * 10^-27 Kg

0.00301 amu = 0.00301 * 1.66 * 10^-27 = 4.997 * 10^-30 Kg

Binding energy = Δmc^2

Binding energy = 4.997 * 10^-30 Kg * (3 * 10^8)^2 = 4.5 * 10^-13 J

7 0
3 years ago
Most of the food that organisms eat can be traced back to? .
9966 [12]

Answer:

A. Plants

Explanation:

Plants are producers, which make their own food. Other organisms, such as rodents, birds, and wild cats, are consumers, which receive their energy from plants or other consumers.

6 0
2 years ago
True/false in order. I need serious help!
Reil [10]

All i know is that #7 is true

4 0
3 years ago
How to balance this equation: <br> Cu(s) + O2(g) --&gt; CuO(s)
Lelu [443]
2Cu(s) + O2(g) --> 2CuO(s)
3 0
3 years ago
125 cm3 of a solution contains 0.25 moles of the solute. What is the concentration of the solution?
jarptica [38.1K]

Answer:

Explanation:

125 cm3 -> 0.125 L

M = no. mole / volume (L)

M = 0.25 / 0.125 = 2 M

3 0
3 years ago
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