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BaLLatris [955]
3 years ago
15

Almost. treating an acyl chloride with a grignard reagent tends to form (via two steps) an alcohol. what reagent forms the keton

e product but does not react with the ketone?

Chemistry
1 answer:
PIT_PIT [208]3 years ago
8 0
Reaction of Acyl Halides with Grignard reagent results in the formation of Ketones in first step. While in second step reaction of Grignard reagent with Ketones results in the formation of Tertiary Alcohols.

If you want to stop the reaction at Ketone stage then you are required to use another mild reactive organometallic compound. In our case we will use Organocuprates. Organocuprates are also known as Gilman Reagents. These reagents does not add to ketones, aldehydes and esters but they can add to acid halides to produce Ketones.

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Difine the term compound​
AlexFokin [52]

Answer:

Its when like two pure substances are like combined into one.

Explanation:

8 0
3 years ago
A student sees an absorbance a=1.140 for his solution that has a concentration of c=1.50*10-4 m using 0.50 cm cuvette. what is t
777dan777 [17]

The molar extinction coefficient is 15,200 M^{-1} cm^{-1}.

The formula to be used to calculate molar extinction coefficient is -

A = ξcl, where A represents absorption, ξ refers molar extinction coefficient, c refers to concentration and l represents length.

The given values are in required units, hence, there is no need to convert them. Directly keeping the values in formula to find the value of molar extinction coefficient.

Rewriting the formula as per molar extinction coefficient -

ξ = \frac{A}{cl}

ξ = \frac{1.140}{1.5*10^{-4}*0.5 }

Performing multiplication in denominator to find the value of molar extinction coefficient

ξ = \frac{1.140}{0.000075}  

Performing division to find the value of molar extinction coefficient

ξ = 15,200 M^{-1} cm^{-1}

Hence, the molar extinction coefficient is  15,200 M^{-1} cm^{-1}.

Learn more about molar extinction coefficient -

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6 0
1 year ago
Which of the following describes the tiny particles that make up matter?
Ksenya-84 [330]
The answer isssssss d
8 0
3 years ago
Use the data in the table above to calculate an approximate ΔH∘ in kilojoules for the synthesis of hydrazine from ammonia:
ankoles [38]
DeltaH formation = deltaH of broken bonds - deltaH of formed bonds

Broken bonds: tiple bond N-N and H-H bond
Formed bonds: N-H and N-N bonds

You also have to take note of the molar coefficients

deltaH formation = <span> [(N≡N) + 2 * (H-H)] - [4 * (N-H) + (N-N)] 
                           = (945 + 2*436) - (4*390 + 240)
                            = 17 kJ/mol

The answer is 17 kJ/mol.</span>
8 0
3 years ago
A more electronegative atom A) will have more attraction to the electrons in a chemical bond. B) is more likely to lose an elect
DIA [1.3K]

Answer: A more electronegative atom will have more attraction to the electrons in a chemical bond.

Explanation:

An atom that is able to attract electrons or shared pair of electrons more towards itself is called an electronegative atom.

For example, fluorine is the most electronegative atom.

Due to its high electronegativity it is able to attract an electropositive atom like H towards itself. As a result, both fluorine and hydrogen will acquire stability by sharing of electrons.

Thus, we can conclude that a more electronegative atom will have more attraction to the electrons in a chemical bond.

6 0
3 years ago
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