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3 years ago

10

Write the complete balanced equation for the reaction between iron (III) oxide (Fe2O3) and water (H2O). You do not need to make

the subscripts smaller; just write them out as regular numbers. For example: Fe2O3 (4 points)

1 answer:

Alina [70]3 years ago

6 0

Fe2O3+3H2O->2Fe(OH)3

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The longest wavelength of light that causes electrons to be ejected from the surface of a potassium metal plate is 539 nm. If 40

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Answer:The longest-wavelength light that causes an electron to be emitted from gaseous lithium atom is 520 nm.

Explanation:

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2 years ago

Which of the following is a measure of the average kinetic energy of the particles in a sample of matter?

cestrela7 [59]

Answer:

<em>Option D. temperature</em>

Explanation:

Indeed it is generally established that <em>temperature is a measure of the kinetic energy ot the particles</em>.

The <em>kinetic energy</em> of a particle is proportional to the product of the mass and the square of the speed. Mathematically, the kinetic energy, KE, is:

KE = (1/2) m × v²

Where m is the mass and v the speed of the particle.

In a sample of matter, not all the particles have the same speed, hence not all the particles have the same kinetic energy.

The kinetic energy and the temperature are related by the Boltzman equation:

KE = (3/2)KT

Where K is a constant (Boltzman constant) and T is the absolute temperature.

Therefore, as you can see from the last equation, <em>the temperaure is a measure of the averate kinetic energy of the particles in a sample of matter</em>.

This is, at a certain temperature, every substance has the same average kinetic energy.

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3 years ago

Neon gas has a volume of 261 ml and a pressure of 108.5 kPa. What volume will the gas occupy at 96.5 kPa if the temperature rema

Tatiana [17]

Answer:

$\large \boxed{\text{293 mL}}$

Explanation:

The temperature and amount of gas are constant, so we can use Boyle’s Law.

$p_{1}V_{1} = p_{2}V_{2}$

Data:

$\begin{array}{rcrrcl}p_{1}& =& \text{108.5 kPa}\qquad & V_{1} &= & \text{261 mL} \\p_{2}& =& \text{96.5 kPa}\qquad & V_{2} &= & ?\\\end{array}$

Calculations:

$\begin{array}{rcl}108.5 \times 261 & =& 96.5V_{2}\\28320 & = & 96.5V_{2}\\V_{2} & = &\dfrac{28320}{96.5}\\\\& = &\textbf{293 mL}\\\end{array}\\\text{The volume of the gas is } \large \boxed{\textbf{293 mL}}$

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