Answer:
51.1 g NH3
The required chemical reaction is given by:
N2 + 3H2 --> 2NH3
4.5 mol H2 × (2 mol NH3/3 mol H2) = 3 mol NH3
molar mass of NH3 is 17.031 g/mol
3 mol NH3 × (17.031 g NH3/1 mol NH3) = 51.1 g NH3
The amount of 1,3-dimethyl urea produced would be 32,458 grams or 32.458 kg while that of carbon dioxide would be 16,214 grams of 16.214 kg
<h3>Stoichiometric problem</h3>
From the equation of the reaction, the mole ratio of methyl isocyanate with the products is 2:1 respectively.
Mole of 42,000 kg of methyl isocyanate = 42000/57 = 736.84 moles
Equivalent mole of 1,3-dimethyl urea = 736.84/2 =368.42 moles
Equivaent mole of carbon dioxide = 736.84/2 =368.42moles
Mass of 368.42 moles 1,3-dimethyl urea = 368.42 x 88.1 = 32,458 grams or 32.458 kg
Mass of 368.42 moles of carbon dioxide = 368.42 x 44.01 = 16,214 grams of 16.214 kg
More on stoichiometric problems can be found here: brainly.com/question/14465605
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