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Lerok [7]
3 years ago
14

Explain how particles transfer with radiation

Physics
1 answer:
just olya [345]3 years ago
3 0

Answer:

they are a form of nuclear energy

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What plate matches almost perfectly with the ring of fire, where most of the world's earthquakes and volcanoes occur? *?
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Pacific Plate<span> and </span>Juan de Fuca<span> 6.</span>
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As a train accelerates uniformly, it passes successive 5-kilometer markers while traveling at velocities 10 m/s and 25 m/s. what
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<span>122.0 km/hr. First let’s make sure all of our units are in the base meter form: i.e. convert 5km to 5000m. (We will convert back to km later). The first thing to do is look at the equation relating velocity, acceleration, and distance: Vf^2 = Vi^2 + 2*a*d, where Vf is final velocity, Vi is initial velocity, a is acceleration, and d is distance. 25^2 = 10^2 + 2*a*5000 =?> 625 = 100 +10000a => a= 0.0525m/s^2. Now that we have acceleration, we can use the same equation again with different numbers.: Vf^2 = Vi^2 + 2*a*d = 25^2 + 2*0. 0525m*5000 = 625 + 525 =1150 => Vf^2 = 1150 => 33.9m/s. Convert to km/hour: 33.9m/s * 1km/1000m *60s/1min * 60min/ 1 hr = 122.0 km/hr.</span>
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4 years ago
An electric fence displays a warning sign about voltage and amperage of the fence. How would amperage and voltage affect the pow
aleksley [76]
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3 years ago
A small object with mass 1.30 kg is mounted on one end of arod
Julli [10]

Answer:

(a) I_{system} = 1.014\ kg.m^{2}

(b) \tau = 0.0179\ N-m

Solution:

As per the question:

Mass of the object, m = 1.30 kg

Length of the rod, L = 0.780 m

Angular speed, \omega = 5010\ rev/min

Now,

(a) To calculate the rotational inertia of the system about the axis of rotation:

Since, the rod is mass less, the moment of inertia of the rotating system and that of the object about the rotation axis will be equal:

I_{system} = ML^{2} = 1.30\times (0.780)^{2} = 0.791\ kg.m^{2}

(b) To calculate the applied torque required for the system to rotate at constant speed:

Drag Force, F = 2.30\times 10^{- 2}\ N

\tau = FLsin\theta 90 = 2.30\times 10^{- 2}\times 0.780\times 1 = 0.0179\ N-m

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3 years ago
A cylindrical tube has an inner radius of r1 and an outer radius of r2. Using the heat equation, derive an expression for the st
PIT_PIT [208]

Answer:

see attachment

Explanation:

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