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miskamm [114]
3 years ago
13

What is 2m+n =k for M

Physics
1 answer:
kotykmax [81]3 years ago
5 0
Answer : M= k-n/2
Subtract n from each side
2m=n-k
Divide out 2 from both sides to get M alone
m= k-n/2
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A large container contains a large amount of water. A hole is drilled on the wall of the container, at a vertical distance h = 0
barxatty [35]

Answer:

Velocity = 3.25[m/s]

Explanation:

This problem can be solved if we use the Bernoulli equation: In the attached image we can see the conditions of the water inside the container.

In point 1, (surface of the water) we have the atmospheric pressure and at point 2 the water is coming out also at atmospheric pressure, therefore this members in the Bernoulli equation could be cancelled.

The velocity in the point 1 is zero because we have this conditional statement "The water surface drops very slowly and its speed is approximately zero"

h2 is located at point 2 and it will be zero.

(P_{1} +\frac{v_{1}^{2} }{2g} +h_{1} )=(P_{2} +\frac{v_{2}^{2} }{2g} +h_{2} )\\P_{1} =P_{2} \\v_{1}=0\\h_{2} =0\\v_{2}=\sqrt{0.54*9.81*2}\\v_{2}=3.25[m/s]

4 0
3 years ago
20 points+ Brainliest
Helen [10]

Answer:

The answer is B. hope this helps

Explanation:

3 0
3 years ago
You are pushing a rock along level ground and making the rock speed up. How does the size of the force you exert on the rock com
Aneli [31]

Answer:

The forces are of the same magnitude just opposite directions

Explanation:

Newton's Third law tells us that if body A exerts a force on body B, then B exerts an equal but opposite force on body B. so as you continue to push the rock causing it to accelerate, the rock also continues to push back at you by an equal force in the opposite direction.

4 0
3 years ago
A 4.0 Ohms resistor, an 8.0 Ohms resistor, and a 12.0 Ohms resistor are connected in series with a 24.0 V battery. Calculate the
Flura [38]

Answer:

RESISTANCE=(4+8+12)Ohms

=24 ohms

V=IR

24= I ×24

I= 24/24

I= 1 A

CURRENT IS 1 A

8 0
3 years ago
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A proton is projected perpendicularly into a magnetic field that has a magnitude of 0.50 T. The field is then adjusted so that a
bixtya [17]

Answer:

B_e = 2.72 \times 10^{-4} T

Explanation:

As we know that when charge particle is projected in perpendicular magnetic field then the radius of the charge particle is given as

F = qvB

\frac{mv^2}{r} = qvB

now we have

r = \frac{mv}{qB}

since here radius of proton and electron will be same

so we will have

r_e = r_p

\frac{m_e v}{q_e B_e} = \frac{m_p v}{q_p B_p}

so we have

B_e = \frac{B_p m_e}{m_p}

given that

B_p = 0.50 T

m_e = 9.11 \times 10^{-31} kg

m_p = 1.67 \times 10^{-27} kg

so we have

B_e = \frac{0.50(9.11\times 10^{-31})}{1.67\times 10^{-27}}

B_e = 2.72 \times 10^{-4} T

4 0
3 years ago
Read 2 more answers
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