Explanation:
Given that,
A student travels 11 m north and then turns around to travel 25 m south.
Total time, t = 12 s
The total distance or the total path covered by the student is equal to 11 m + 25 m = 36 m
Displacement of the student or the shortest path covered is d = 25-11 = 14 m
(a) The student's average speed = total distance/total time

(b) The student's average velocity = total displacement/total time

The total energy of the system is 88.2 J
Explanation:
The total (mechanical) energy of an object is given by:

where
PE is the potential energy
KE is the kinetic energy
At the starting point, the object is at rest: this means that its kinetic energy is zero, so all its energy is potential energy, which is given by

where
m is the mass of the object
g is the acceleration of gravity
h is the height of the object
In this problem, we have (at point A):
m = 3.0 kg

h = 3.0 m
Substituting, we find:

Learn more about potential energy:
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Answer:
a) V ≈ 125 m/s; b) Δt = 13.24 s; c) ΔS ≈ 1450 m
Explanation:
a) We have just to calculate the vector resultant.
V² = 106² + 66.2²
V² = 15618.44
V ≈ 125 m/s
b) The time of flight is equal to the time to reach the maximum height summed to the time to reach the land.
In vertical:
V = V₀ + a * t
V = 66.2 - g * t
0 = 66.2 - 9.8 * t
t ≈ 6.76 s
So: Δt = 13.24 s
c) In horizontal:
V = ΔS / Δt
106 = ΔS / 13.52 ⇒ ΔS = 106 * 13.52
ΔS = 106 * 13.52
ΔS = 1433,12
ΔS ≈ 1450 m
Answer:
a. Picture attached
b. V, X
c. 
d. It makes sense cosidering that a normal heart beat rate is between 60 and 100 beats per minute (bpm).
Explanation:
First we have to identify the unknown of this problem:

Considering the characteristics of the problem and that distance and velocity are specified, the acceleration is constant, for that reason we use the equations of uniformly accelerated motion as follows:

If we reorganize the equations, considering that
and
are zero because motion starts from rest , we have:

Finally, the analysis of the result leaves us to understand why the normal heart beat rate varies between 60 and 100 bpm.