Answer:
a) The speed of the slider is 4.28 in/s
b) The velocity vector is 2.33 in/s
Explanation:
a) According to the diagram 1 in the attached image:

Also:
![v_{C} =v_{A}+w_{AC}*r_{C/A}\\v_{Ci}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC} \\6.883&-9.829&0\end{array}\right]\\v_{Ci}=-3j+(0+9.829w_{AC} i-(0-6.883w_{AC})j\\v_{Ci}=9.829w_{AC}i+(-3+6.883w_{AC})j](https://tex.z-dn.net/?f=v_%7BC%7D%20%3Dv_%7BA%7D%2Bw_%7BAC%7D%2Ar_%7BC%2FA%7D%5C%5Cv_%7BCi%7D%3D-3j%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%26w_%7BAC%7D%20%5C%5C6.883%26-9.829%260%5Cend%7Barray%7D%5Cright%5D%5C%5Cv_%7BCi%7D%3D-3j%2B%280%2B9.829w_%7BAC%7D%20i-%280-6.883w_%7BAC%7D%29j%5C%5Cv_%7BCi%7D%3D9.829w_%7BAC%7Di%2B%28-3%2B6.883w_%7BAC%7D%29j)
If we comparing both sides of the expression:


b) According to the diagram 2 in the attached image:

![v_{C}=v_{A}+w_{AC}r_{C/A}\\v_{C}=-3j+\left[\begin{array}{ccc}i&j&k\\0&0&w_{AC}\\7.713&-9.192&0\end{array}\right] \\v_{Ci}=-3j+(9.192w_{AC})i+7.713w_{AC}j\\v_{Ci}=9.192w_{AC}i+(7.713w_{AC}-3)j](https://tex.z-dn.net/?f=v_%7BC%7D%3Dv_%7BA%7D%2Bw_%7BAC%7Dr_%7BC%2FA%7D%5C%5Cv_%7BC%7D%3D-3j%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%26w_%7BAC%7D%5C%5C7.713%26-9.192%260%5Cend%7Barray%7D%5Cright%5D%20%5C%5Cv_%7BCi%7D%3D-3j%2B%289.192w_%7BAC%7D%29i%2B7.713w_%7BAC%7Dj%5C%5Cv_%7BCi%7D%3D9.192w_%7BAC%7Di%2B%287.713w_%7BAC%7D-3%29j)
Comparing both sides of the expression:

![v_{B}=v_{C}+w_{AC}r_{B/C}\\v_{B}=3.57i+\left[\begin{array}{ccc}i&j&k\\0&0&0.388\\-3.856&4.59&0\end{array}\right] \\v_{B}=3.57i+(0-1.78)i-(0+1.499)j\\v_{B}=1.787i-1.499j\\|v_{B}|=\sqrt{1.787^{2}+1.499^{2} } =2.33in/s](https://tex.z-dn.net/?f=v_%7BB%7D%3Dv_%7BC%7D%2Bw_%7BAC%7Dr_%7BB%2FC%7D%5C%5Cv_%7BB%7D%3D3.57i%2B%5Cleft%5B%5Cbegin%7Barray%7D%7Bccc%7Di%26j%26k%5C%5C0%260%260.388%5C%5C-3.856%264.59%260%5Cend%7Barray%7D%5Cright%5D%20%20%5C%5Cv_%7BB%7D%3D3.57i%2B%280-1.78%29i-%280%2B1.499%29j%5C%5Cv_%7BB%7D%3D1.787i-1.499j%5C%5C%7Cv_%7BB%7D%7C%3D%5Csqrt%7B1.787%5E%7B2%7D%2B1.499%5E%7B2%7D%20%20%7D%20%3D2.33in%2Fs)
Answer:
P = 3000 Pa
Explanation:
Weight of Dorji, W = F = mg = 1500 N
The total surface area of soles of his feet is 0.5 m²
We need to find the pressure exerted by his body on the ground. The pressure is equal to the force acting per unit area. So,

So, the pressure exerted by his body on the ground is 3000 Pa.
Answer:
0.045 J
Explanation:
The work done on a charge moving through a potential difference is given by

where
W is the work done
q is the charge
is the potential difference
In this problem, we have
q = 0.0050 C is the charge
is the potential difference
Using the formula, we find the work done:

In physics we refer to how heavy the object is as the mass.
Fg = mass x acceleration due to gravity
Force is directly proportional to mass, thus if force of gravity increases mass also increases.