Answer:
(a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.
Explanation:
Given that,
Mass of block =1.60 kg
Force constant = 315 N/m
Speed = 13.0 m/s
(a). We need to calculate the amplitude of the motion
Using conservation of energy
Put the value into the relation
(b). We need to calculate the block’s maximum acceleration
Using formula of acceleration
Put the value into the formula
(c). We need to calculate the maximum force the spring exerts on the block
Using formula of force
Put the value into the formula
Hence, (a). The amplitude of the motion is 0.926 m.
(b). The block’s maximum acceleration is 182.31 m/s².
(c). The maximum force the spring exerts on the block is 291.69 N.
6b: impulse is change in momentum. Change in momentum p=m[v(final)-v(initial). Final velocity is zero and initial velocity is the one you calculated before impact: -15.7 since it’s going down. Now plug in numbers and you get 78.5 in the upward direction.
6c: change in momentum p=Ft. we already calculated change in momentum. So plug it into equation and solve for t. 78.5/655= 0.119 s
Apply the same idea for question 7. Hope this helped
It should be D work and time because power = work / time
The answer for the question is c
Answer: the radius of the satellite's orbit is r = 8.78×10⁷m
Explanation:
given the time period, T= 3days
converting the time in days to seconds is given as;
time, T=(3*24*60*60) sec
T=259200 sec
from the force relation;
mv²/r = Gm×M/r²
v²=G×M/r ---------------(1)
and
V=2pi×r/T
V²=4×pi²×r²/T²
====>
from equation (1)
, we have
4×pi²×r²/T²=G×M/r
this becomes; 4×pi²×r³/T² = G×M
r³ = G×M×T²/(4pi²)
r³ = 6.67×10⁻¹¹×(5.97×10²⁴)×(259200)²/(4pi²)
==> r=8.78×10⁷m
radius of the orbit, r=8.78×10⁷ m