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Debora [2.8K]
3 years ago
15

An airplane flies in a horizontal circle of radius 500 m at a speed of 150 m/s. If the radius were changed to 1000 m, but the sp

eed remained the same, by what factor would its centripetal acceleration change?
Physics
1 answer:
laila [671]3 years ago
7 0

Answer:

The centripetal acceleration changed by a factor of 0.5

Explanation:

Given;

first radius of the horizontal circle, r₁ = 500 m

speed of the airplane, v = 150 m/s

second radius of the airplane, r₂ = 1000 m

Centripetal acceleration is given as;

a = \frac{v^2}{r}

At constant speed, we will have;

v^2 =ar\\\\v = \sqrt{ar}\\\\at \ constant\ v;\\\sqrt{a_1r_1} = \sqrt{a_2r_2}\\\\a_1r_1 = a_2r_2\\\\a_2 = \frac{a_1r_1}{r_2} \\\\a_2 = \frac{a_1*500}{1000}\\\\a_2 = \frac{a_1}{2} \\\\a_2 = \frac{1}{2} a_1

a₂ = 0.5a₁

Therefore, the centripetal acceleration changed by a factor of 0.5

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How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W
ArbitrLikvidat [17]

Complete question:

How many x-ray photons per second are created by an x-ray tube that produces a flux of x rays having a power of 1.00 W. Assume the average energy per photon in 78.0 keV.

Answer:

The number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec

Explanation:

Given;

power of the flux produced, P = 1 W = 1 J/s

energy per photon, E = 78 keV

Convert the energy per photon to J

E = 78 x 10³ x 1.6 x 10⁻¹⁹ = 1.248 x 10⁻¹⁴ J / photon

let the number of photons = n

n(1.248 x 10⁻¹⁴ J / photon) = 1 J/s

n = \frac{1 \ J/s}{1.248 \times 10^{-14}\  J/photon } = 8.01 \times 10^{13} \ photons/s

Therefore, the number of x-ray photons per second created by the x-ray tube is 8.01 x 10¹³ photons/sec

8 0
2 years ago
The equation for momentum is p = mv, where p is momentum, m is mass, and v
Tasya [4]

Answer:

p = mv, where p is momentum, m is mass, and v is velocity.

a. ) m = 12kg v = 14m/s

Momentum (p) = mv

= 12kg × 14m/s

= 168kg•m/s

b.) momentum (p) = 35 kg•m/s

velocity = 3m/s

p = mv

make m the subject

divide both sides by v

we get

m = p/v

Therefore m is

m = 35 kg•m/s / 3m/s

m = 11.67kg

Therefore the mass of the object is 11.67kg

Hope this helps

3 0
3 years ago
Where is our solar system located in the Milky Way?      
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Our solar system is located in the outer reaches of the Milky Way Galaxy, which is a spiral galaxy .
7 0
3 years ago
the thermometer has its stem marked in millimeter instead of degree Celsius. the lower fixed point is 30mm and the upper fixed p
Lorico [155]

10°c

Explanation:

Given parameter;

Lower fixed point = 30mm

Upper fixed point = 180mm

Reading = 45mm

Unknown:

The degree celcuis temperature at 45mm = ?

Solution:

To solve this problem we simply compare the mm- scale to the celcius - scale that we know.

The upper fixed point is the boiling point of water

Lower fixed point is the freezing point of water

This shows that both the upper and lower fixed point of both thermometers are the same;

         mm-scale          °c scale

          180mm               100°c

            45mm                x

          30mm                  0°c

Solving;

                     \frac{x - 0}{100 -0} =  \frac{45 - 30 }{180- 30}

   x (150) = 100  x 15

   x = 10°c

learn more:

Temperature scales brainly.com/question/1603430

#learnwithBrainly

 

7 0
3 years ago
A block of ice is sliding down a ramp of slope 40 to the horizontal. What is the rate of acceleration of the block? Assume the f
uysha [10]

The given problem can be exemplified in the following diagram:

Since there is no friction or any other external force, the only force acting in the direction of the movement is the component of the weight of the block, therefore, applying Newton's second law:

\Sigma F=ma

Replacing the values:

mg\sin 40=ma

We may cancel out the mass:

g\sin 40=a

Using the gravity constant as 9.8 meters per square second:

9.8\frac{m}{s^2}\sin 40=a

Solving the operations:

6.3\frac{m}{s^2}=a

Therefore, the acceleration is 6.3 meters per square second.

8 0
1 year ago
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