Answer:
6(3h+5k)
Step-by-step explanation:
18h+30k
Factors of 18:
1, 2, 3, 6, 9, 18
Factors of 30:
1, 2, 3, 5, 6, 10, 15, 30
GCF of 18 and 30: 6
18h+30k = 6(3h+5k)
Check your answer:
6(3h+5k)
6(3h) + 6(5k)
18h + 30k
Hope this helps!
1 and 3 are odd while 2 and 4 are even. Odd numbers end in 1,3,5,7,9 while even numbers end in 0,2,4,6,8. Please Mark Brainliest!!!
Step-by-step explanation:
Using the properties of logarithms, the left side of the equation becomes

while the right hand side becomes

so we end up with

Answer:
1536 square inches
Step-by-step explanation:
In units of 5 feet, the backdrop is 3 units wide and 2 units high, for a total area of 3×2 = 6 square units.
Those same units on the scale drawing are each 16 inches. One square unit on the scale drawing is (16 in)² = 256 in². So, 6 of them have an area of ...
6 × 256 in² = 1536 in²
Megan:
x to the one third power =

<span>x to the one twelfth power = </span>

<span>The quantity of x to the one third power, over x to the one twelfth power is:
</span>

<span>
Since </span>

then

Now, just subtract exponents:
1/3 - 1/12 = 4/12 - 1/12 = 3/12 = 1/4

Julie:
x times x to the second times x to the fifth = x * x² * x⁵
<span>The thirty second root of the quantity of x times x to the second times x to the fifth is
</span>
![\sqrt[32]{x* x^{2} * x^{5} }](https://tex.z-dn.net/?f=%20%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%20)
<span>
Since </span>

Then
![\sqrt[32]{x* x^{2} * x^{5} }= \sqrt[32]{ x^{1+2+5} } =\sqrt[32]{ x^{8} }](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7Bx%2A%20x%5E%7B2%7D%20%2A%20x%5E%7B5%7D%20%7D%3D%20%5Csqrt%5B32%5D%7B%20x%5E%7B1%2B2%2B5%7D%20%7D%20%3D%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D)
Since
![\sqrt[n]{x^{m}} = x^{m/n} }](https://tex.z-dn.net/?f=%20%5Csqrt%5Bn%5D%7Bx%5E%7Bm%7D%7D%20%3D%20x%5E%7Bm%2Fn%7D%20%7D%20)
Then
![\sqrt[32]{ x^{8} }= x^{8/32} = x^{1/4}](https://tex.z-dn.net/?f=%5Csqrt%5B32%5D%7B%20x%5E%7B8%7D%20%7D%3D%20x%5E%7B8%2F32%7D%20%3D%20x%5E%7B1%2F4%7D%20)
Since both Megan and Julie got the same result, it can be concluded that their expressions are equivalent.