The product is negative 81 t squared + 16 ⇒ 2nd answer
Step-by-step explanation:
The product of two binomials (ax + b)(cx + d), where a, b, c, and d are constant
- Multiply (ax) by (cx) ⇒ 1st × 1st
- Multiply (ax) by (d) and (b) by (cx) ⇒ ext-reams and nears
- Add the two products ⇒ like terms
- Multiply (b) by (d) ⇒ 2nd × 2nd
Let us find the product of (9 t - 4) and (-9 t - 4)
Multiply the 1st two terms
∵ (9 t)(-9 t) = -81 t²
Multiply the ext-reams
∵ (9 t)(-4) = -36 t
Multiply the nears
∵ (-4)(-9 t) = 36 t
Add the like terms
∵ -36 t + 36 t = 0
Multiply the 2nd two terms
∵ (-4)(-4) = 16
Write the answer
∴ (9 t - 4)(-9 t - 4) = -81 t² + 0 + 16
∴ (9 t - 4)(-9 t - 4) = -81 t² + 16
The product is -81 t² + 16
Learn more:
You can learn more about the product of algebraic expressions in brainly.com/question/1617787
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Answer:
<em>B. 9 < 7 or x > 16.</em>
Step-by-step explanation:
<em>I had the same question and the answer was B.</em>
-6x+8 I thinkz thtats the correct answer
Answer:
see explanation
Step-by-step explanation:
Given D(3, 2 ) → D'(2, 4 )
The x- coordinate of D' is 1 less than D and the y- coordinate of D' is 2 more than D, thus the translation rule is
(x, y ) → (x - 1, y + 2 )
Apply this rule to points O and G
O( 2, - 4 ) → O'(2 - 1, - 4 + 2 ) → O'(1, - 2 )
G(- 1, - 1 ) → G'(- 1 - 1, - 1 + 2 ) → G'(- 2, 1 )
