Can anyone help me get caught up on edge ill pay $ and give u user and pass

Solve<br> 11x-6y=3 ; 5x-8y=-25

Fiesta28 [93]

Answer: x=3 and y=5

Step-by-step explanation: 11x-6y=3, 5x-8y=-25

11x-6y+6y=3+6y

11x/11=3/11+6y/11

x=3+6y/11

5(3+6y/11)-8y(11)/11

5(6y+3)-88y/11

30y+15-88y/11

88y-30y

58y

11(15-58y)/11=11(-25)

15-58y-15=-275-15

-58y/-58=-290/-58

y=5

x=3+6(5)/11

3+30

33

33/11

x=3

x=3, y=5

6 0

3 years ago

The ratio of height of a bonsai ficus tree to the height of a full-size ficus trees is 1:9 the bonsai ficus is 6 inches tall wha

kotykmax [81]

To solve this relationship simply make them equal to each other and find the correct value to multiply both the top and cotton numbers and solve,
In this case because of the initial ratio of 1:9, if the bonsai ficus is 6 then 54 inches would be the full size.

8 0

3 years ago

The art club had an election to select a president. 56 members voted in the election and 24 did not vote. What percentage of the

Brrunno [24]

Answer:

56 + 24 = 80

56 X 100 = 5600

5600/80 = 70%

6 0

3 years ago

Need help pls<br>thank you in advance

ira [324]

Answer:

<u />

$\textsf{Mean}\:\overline{X}=\sf \dfrac{\textsf{sum of all the data values}}{\textsf{total number of data values}}$

$\implies \sf Mean\:(Nilo)=\dfrac{5+6+14+15}{4}=\dfrac{40}{4}=10$

$\implies \sf Mean\:(Lisa)=\dfrac{8+9+11+12}{4}=\dfrac{40}{4}=10$

<h3><u>Standard Deviation</u></h3>

$\displaystyle \textsf{Standard Deviation }s=\sqrt{\dfrac{\sum X^2-\dfrac{(\sum X)^2}{n}}{n-1}}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Nilo)} & =\sqrt{\dfrac{(5^2+6^2+14^2+15^2)-\dfrac{(5+6+14+15)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{482-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{82}{3}}\\\\& = 5.23\end{aligned}$

$\begin{aligned}\displaystyle \textsf{Standard Deviation (Lisa)} & =\sqrt{\dfrac{(8^2+9^2+11^2+12^2)-\dfrac{(8+9+11+12)^2}{4}}{4-1}}\\\\& = \sqrt{\dfrac{410-\dfrac{40^2}{4}}{3}}\\\\& = \sqrt{\dfrac{10}{3}}\\\\& = 1.83\end{aligned}$

<h3><u>Summary</u></h3>

Nilo has a mean score of 10 and a standard deviation of 5.23.

Lisa has a mean score of 10 and a standard deviation of 1.83.

The <u>mean</u> scores are the <u>same</u>.

Nilo's standard deviation is higher than Lisa's. Therefore, Nilo's test scores are more <u>spread out</u> that Lisa's, which means Lisa's test scores are more <u>consistent</u>.

5 0

2 years ago

Rewrite these in increasing order of length:<br> 133 dm. 433 cm, 308 km, 91 mm

Oksi-84 [34.3K]

$\boxed{91mm$

<h2>Explanation:</h2>

First of all, let's transform each measurement into meter knowing the following relationships:

$1dm=0.1m \\ \\ 1cm=0.01m \\ \\ 1km=1000 m \\ \\ 1mm=0.001m$

Therefore, we can compute the following:

$\bullet \ 133dm \rightarrow 133dm(\frac{0.1m}{1dm})=13.3m \\ \\ \bullet \ 433cm \rightarrow 433cm(\frac{0.01m}{1cm})=4.33m \\ \\ \bullet \ 308km \rightarrow 308km(\frac{1000m}{1km})=308,000m \\ \\ \bullet \ 91mm \rightarrow 91mm(\frac{0.001m}{1mm})=0.091m$

Writing this in increasing order:

$0.091m$

<h2>Learn more:</h2>

jovian planets in order of increasing distance from the Sun: brainly.com/question/12534549

#LearnWithBrainly

7 0

3 years ago